*FaerieLight*
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Homework Statement
Find the limit as n[tex]\rightarrow[/tex][tex]\infty[/tex] of the sequence
an=[tex]\frac{(2n)! 2<sup>2n</sup>}{(n!)<sup>2</sup> (2n+1) 5<sup>2n</sup>}[/tex]
Mark44 said:The ratio test is to be used on terms of an infinite series, [itex]\sum a_n[/itex]. If the limit of the ratio a_(n + 1)/a_n is less than 1, the series converges. You should be able to evaluate the limit of this sequence directly.
The tricky part is evaluating (2n)!/[(n!)^2 (2n + 1)], since 2^(2n)/5^(2n) = (2/5)^(2n) --> 0 as n --> infinity.
Dick said:You can also use the ratio test on a sequence. If |a_(n+1)/a_n| goes to a limit less than 1 then the sequence converges to zero. As it must if the series is to converge. For some reason this doesn't seem to be taught much as a method.
Mark44 said:I don't remember learning about using the ratio test on a sequence, or seeing it in any of the calculus texts I taught out of.