Limits for Rho in Triple Integral for Volume of Solid Bounded by Two Surfaces

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SUMMARY

The discussion centers on finding the volume of a solid bounded above by the surface defined by \(\rho=1+\cos\varphi\) and below by \(\rho=1\). The user initially solved the integral but questioned the limits of integration for \(\rho\), which the professor set from 0 to 1, while the user believed they should be from 1 to \(1+\cos\varphi\). The conversation highlights the importance of verifying integral limits and suggests potential errors in problem setup or interpretation.

PREREQUISITES
  • Understanding of spherical coordinates and their applications in triple integrals.
  • Familiarity with the concept of volume calculation using integrals.
  • Knowledge of the properties of trigonometric functions, particularly cosine.
  • Experience with evaluating multiple integrals in calculus.
NEXT STEPS
  • Review the derivation of volume in spherical coordinates.
  • Study the implications of changing limits of integration in triple integrals.
  • Learn about common errors in integral setup and how to avoid them.
  • Practice solving similar volume problems using different bounding surfaces.
USEFUL FOR

Students in calculus, particularly those studying multivariable calculus, as well as educators and tutors looking to clarify concepts related to triple integrals and volume calculations in spherical coordinates.

HclGuy
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Homework Statement



Find the volume of the solid bounded above by \rho=1+cos\varphi and below by \rho=1

Homework Equations




The Attempt at a Solution



I already solved it but was comparing my answer to my professor's solution, I was wondering why when he did the integration, his limits for \rho were from 0 to 1, wouldn't the limits for rho be 1 to 1+cos\varphi? Thanks
 
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There are any number of reasons why one integral might give the same result as another- since you did not post his complete integral I don't believe we can say why his method works for this particular problem.
 
The thing is, I got a different answer and was not sure if the professor had made an error on the answer key since I already spotted a few other errors on it..but let's see now
\int\int_0^\pi\int_0^1\rho^2\sin\varphi d\rho d\varphi d\theta
outer limits are from 0 to 2pi
I was just wondering why his limits for \rho were from 0 to 1. I thought it would be from 1 to 1+cos\varphi
 
You may have copied the problem wrong or he may have set it up wrong himself. Have you asked your professor?
 

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