SOLVED, thanks to Dick and viciousp! 1. The problem statement, all variables and given/known data The question asks: Find the limit. Use L'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. If L'Hospital's Rule doesn't apply, explain why. Limit as x approaches pi/2 from the right (+) of given equation: lim [x -> (pi/2)+] of [(cos x) / (1 - sin x)] 2. Relevant equations Possibly trig identity: tan x = sin x / cos x L'Hosptial's Rule: lim(x->a) of f(x)/g(x) = lim(x->a) of fprime(x) / gprime(x) 3. The attempt at a solution lim [x -> (pi/2)+] of [(cos x) / (1 - sin x)] = lim [x -> (pi/2)+] of [(-sin x) / (-cos x)] ---> using L'Hosptial's Rule = lim [x -> (pi/2)+] of [(tan x)] ---> using trig identity tan x = sin x / cos x --> tan (pi/2) is undefined. Therefore my solution would be infinity. I don't understand how the answer is negative infinity. LOL, my answer disagreeing with the book again... lol... I know it's probably me. Could someone please explain to me how it's negative infinity and not infinity?