Limits of Trigonometric Functions.

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SUMMARY

The limit of the expression limx → 0 sin(2e/x3) * arctan(x) is evaluated in the context of trigonometric functions. The key takeaway is that while arctan(0) equals 0, the behavior of sin(2e/x3) as x approaches 0 is undefined. Therefore, the limit does not simplify to 0, as the undefined nature of sin(2e/x3) cannot be dismissed. The correct approach involves recognizing that sin(u) is bounded between -1 and 1 for all real u.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with trigonometric functions and their properties
  • Knowledge of the arctangent function and its behavior near zero
  • Ability to manipulate and evaluate limits involving indeterminate forms
NEXT STEPS
  • Study the Squeeze Theorem for evaluating limits involving bounded functions
  • Learn about L'Hôpital's Rule for resolving indeterminate forms
  • Explore the behavior of sin(x) and its limits as x approaches infinity
  • Investigate the properties of the arctan function and its limits
USEFUL FOR

Students in calculus, particularly those tackling limits involving trigonometric functions, as well as educators looking for examples of limit evaluations in advanced mathematics.

gabyoh23
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Limits of Trigonometric Functions. URGENT!

Homework Statement


Evaluate stackrel{lim}{x [tex]\rightarrow[/tex]0}[/tex] [sin(\frac{2e}{x3}) \bullet (arctanx)]


Homework Equations


All I know is that the equation stackrel{lim}{x [tex]\rightarrow[/tex]0}[/tex] [tex]\frac{sin x}{x}[/tex] = 1 might be helpful, but I'm not sure how to apply it to this particular problem.


The Attempt at a Solution


I talked to a friend of mine who's in Calc III, and she said that the whole limit would be equal to 0 since arctan(0) = 0, and sin[tex]\frac{2e}{x<sup>3</sup>}[/tex] is undefined, and the zero beats out the undefined value. This might be right, but how would I show that mathematically?

All help is greatly appreciated as I'm kind of in a crunch here :)
 
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gabyoh23 said:

Homework Statement


Evaluate stackrel{lim}{x [tex]\rightarrow[/tex]0}[/tex] [sin(\frac{2e}{x3}) \bullet (arctanx)]


Homework Equations


All I know is that the equation stackrel{lim}{x [tex]\rightarrow[/tex]0}[/tex] [tex]\frac{sin x}{x}[/tex] = 1 might be helpful, but I'm not sure how to apply it to this particular problem.


The Attempt at a Solution


I talked to a friend of mine who's in Calc III, and she said that the whole limit would be equal to 0 since arctan(0) = 0, and sin[tex]\frac{2e}{x<sup>3</sup>}[/tex] is undefined, and the zero beats out the undefined value. This might be right, but how would I show that mathematically?

All help is greatly appreciated as I'm kind of in a crunch here :)
Here's your corrected limit expression.

Evaluate [tex]lim_{x \rightarrow 0} sin(\frac{2e}{x^3}) arctanx[/tex]

Your friend is leading you astray. It's not necessarily true that an expression tending to zero "beats out" an undefined value. What is true is that -1 <= sin(u) <= 1 for all real values of u.
 


Thanks for correcting my formatting. I was in a rush, and I accidentally hit the "submit post" button before previewing it.

Thanks for the input!
 

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