Line Image Transformation with 3x3 Matrix - Vector Solution

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Homework Help Overview

The discussion revolves around a linear transformation represented by a 3x3 matrix applied to a vector form of a line equation. Participants are exploring the implications of this transformation and the role of parameters within the context of vector mathematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to determine the images of lines under a matrix transformation and are questioning the meaning of the parameter 'n' in the context of the line equation. There is also a discussion about when to use the inverse of a matrix in relation to transformations.

Discussion Status

The conversation is ongoing, with some participants seeking clarification on the use of the inverse matrix and its relationship to finding images versus inverse images. There is a recognition of confusion regarding the transformation process and the role of parameters.

Contextual Notes

Participants are grappling with the definitions and applications of matrix transformations and inverse matrices, indicating a need for further exploration of these concepts in the context of the problem presented.

takercena
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Please help me solve this question:
Question: Find the images of the lines r = i - j + n(i + j + k) under transformation
M (matrix 3 x 3) =
(2 1 4)
(3 5 1)
(1 2 0)
in vector form.
 
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The image under the transformation is just that matrix times the vector? But what is n? My first thought was that it was the parameter but then that is just a single line. If that is correct then r= i- j+ n(i+ j+ k)= (n+1)i+ (n-1)j+ nk and its image is
[tex]\left[\begin{array}{ccc}2 & 1 & 4 \\ 3 & 5 & 1 \\ 1 & 2 & 0\end{array}\right]\left[\begin{array}{c} n+1 \\ n-1 \\ n\end{array}\right][/tex]
 
Thank you. There is some confusion here. I am confuse when to use inverse matrix to find transformation. Can you explain this. Example : 1. Find the images under the transformation
 
Last edited:
I have no idea what you mean by that. You use the inverse matrix in order to find an "inverse image": x such that Mx= y. Given a matrix M, the image of x is, by definition Mx.
 

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