Line integrals distance elements

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Discussion Overview

The discussion revolves around the concepts of line integrals, specifically the distinction between the vector elements of distance denoted as ds and dr. Participants explore their definitions, applications, and notational differences in various contexts, including curved paths and straight lines.

Discussion Character

  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant expresses confusion about the difference between ds and dr, questioning whether ds applies to all paths and if dr is only for straight lines.
  • Another participant suggests that d\vec{r} and d\vec{s} represent the same concept, indicating that both can be used for curved lines and that the difference lies in notation preferences among professors.
  • A third participant defines ds as the square root of the dot product of d\vec{r} with itself, asserting that ds equals dr and suggesting that ds may refer to paths in spaces beyond normal space.
  • A later reply argues that ds and dr are not the same, explaining that ds is an element of a curve while dr represents a straight line segment, emphasizing that ds is measured along the curve.
  • This reply also describes a geometric interpretation involving vectors and limits, stating that dr and ds coincide only at a specific point on the curve.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the equivalence of ds and dr, with some asserting they are the same while others maintain they are distinct concepts. The discussion remains unresolved regarding the precise relationship between these two notations.

Contextual Notes

Participants mention various contexts for ds and dr, including curved paths and different types of spaces, but do not clarify the implications of these contexts on their definitions.

y.moghadamnia
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in line integrals we always need a vector element of distance. I can't understand the difference between ds and dr. is ds for all kinds of paths (even curly ones) and dr only for straight lines, or theyre the same? I am confused, or maybe dr is just the magnitude of ds, and the vector here is the ds,which one is true?
 
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If \vec{r} \ represents the possible points on some path, then d \vec{r} and d \vec{s} \ mean the same thing. And also dr and ds would mean the same thing.
So they are both used for curly lines. I think some professors will write one, and others write the other. Its just a different notation.
 
For example, ds is defined as:
ds = \sqrt{ d \vec{r} \cdot d \vec{r} }
and so ds = dr. I think ds is also used to mean paths through spaces other than normal space (i.e. spacetime or momentum-space). So ds just means a general path integral, but dr is specifically through normal space.
So if your teacher says "ds as a path through space" then it does mean the same as dr.
 
Good morning, y.moghdamnia, welcome to physics forums.

dr and ds are not the same thing at all. We actually want ds, but use dr as the next best thing.

Since you are approaching line integrals through vectors here is a vector explanation of what is going on.

With reference to the attached diagram.

ds is an element of any suitable curve C.
Note ds is curved and measured along C.

In order to specifiy the curve we consider a centre O and a vector r from O to any point (A) on the curve.

Now let us move along the curve to another point, B.

the vector r changes to another vector r+dr
The distance along the curve is ds. Note it is curved.

In order to recover dr we take the vector difference (r+dr - r) = dr
Note that this is like all vectors, a straight line. Further it is tangent to the curve at A.
Further note that this vector difference is given by the closure of triangle AOB as in the diagram.

Now we are doing some (simple) vector calculus, which follows the same pattern as elementary scalar calculus you are already familiar with.

We let dr approach smaller and smaller values (zero) and take the limit, where we find that
dr and ds concide. But only at A.

does this help?
 

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