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Linear Algebra Change Matrices: Seems too simple

  1. Apr 12, 2010 #1
    1. The problem statement, all variables and given/known data
    EDIT: There turns out to be a problem with the question, that's why it wasn't working. If anyone sees it they're just going to get confused, so I'm taking it off.


    2. Relevant equations



    3. The attempt at a solution
     
    Last edited: Apr 12, 2010
  2. jcsd
  3. Apr 12, 2010 #2

    radou

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    Homework Helper

    Never heard of "CA(v)", but if it's what you defined it to be, this looks correct.
     
  4. Apr 12, 2010 #3
    Oh, well maybe I should give the definition! That probably would have been a good idea, haha.

    A is an ordered basis in Rn and A = {e1, ... en}

    v is a vector in Rn, and v = v1e1 + ... + vnen for some numbers v1 ... vn.

    Then CA(v) = [v1 ... vn]T.
     
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