Linear algebra: determinants (proof)

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SUMMARY

The discussion centers on proving the determinant of a block matrix M = [A B:O C], where A is a kxk matrix, C is a pxp matrix, and O is a zero matrix. The correct conclusion is that det(M) = det(A)det(C). The user initially misapplied scalar multiplication rules to matrices, leading to confusion in their proof attempt. After receiving feedback, the user recognized their error in treating matrices as scalars.

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yoda05378
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hi, i seem to have some trouble proving:

Suppose M = [A B:O C], where A is a kxk matrix, C is a pxp matrix, and O is a zero matrix. Show that det(M) = det(A)det(C).


my attempt at a proof:

det(M) = det(A)det(C)

det[A B:O C] = det(A)det(C)

AC - OB = det(A)det(C)

AC = det(A)det(C) <-- doesn't make sense!

please point out where my logic failed.
 
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nevermind. i figured out where i went wrong (i treated the matrices as if they were scalar, stupid me). thanks for all the help :sarcasm:
 

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