VinnyCee
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Let A be a 4 X 4 matrix, and let \overrightarrow{b} and \overrightarrow{c} be two vectors in \mathbb{R}^4. We are told that the system A\,\overrightarrow{x}\,=\,\overrightarrow{b} has a unique solution. What can you say about the number of solutions of the system A\,\overrightarrow{x}\,=\,\overrightarrow{c}?
MY ANSWER:
The only way that the system A\,\overrightarrow{x}\,=\,\overrightarrow{c} has a unique solution is if A is invertable.
A is to be invertable.
A\,\overrightarrow{x}\,=\,\overrightarrow{c} has a unique solution.
But maybe the solution set \overrightarrow{c} does not have a unique solution because A is not truly invertable?
MY ANSWER:
The only way that the system A\,\overrightarrow{x}\,=\,\overrightarrow{c} has a unique solution is if A is invertable.
A is to be invertable.
A\,\overrightarrow{x}\,=\,\overrightarrow{c} has a unique solution.
But maybe the solution set \overrightarrow{c} does not have a unique solution because A is not truly invertable?
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