Linear Algebra: Does Ax=c Have a Unique Solution?

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For the system A\,\overrightarrow{x}\,=\,\overrightarrow{b} to have a unique solution, matrix A must be invertible. If A is indeed invertible, then the system A\,\overrightarrow{x}\,=\,\overrightarrow{c} will also have a unique solution. However, if A is not truly invertible, it raises questions about the uniqueness of solutions for A\,\overrightarrow{x}\,=\,\overrightarrow{c}. The discussion emphasizes that the invertibility of matrix A is crucial for determining the uniqueness of solutions in both systems. Thus, the uniqueness of solutions is directly tied to the properties of matrix A.
VinnyCee
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Let A be a 4 X 4 matrix, and let \overrightarrow{b} and \overrightarrow{c} be two vectors in \mathbb{R}^4. We are told that the system A\,\overrightarrow{x}\,=\,\overrightarrow{b} has a unique solution. What can you say about the number of solutions of the system A\,\overrightarrow{x}\,=\,\overrightarrow{c}?

MY ANSWER:

The only way that the system A\,\overrightarrow{x}\,=\,\overrightarrow{c} has a unique solution is if A is invertable.

A is to be invertable.

A\,\overrightarrow{x}\,=\,\overrightarrow{c} has a unique solution.

But maybe the solution set \overrightarrow{c} does not have a unique solution because A is not truly invertable?
 
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If Ax=b has a unique solution, what does that tell you about the matrix A?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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