LINEAR ALGEBRA: Find vectors that span the image of A

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To find vectors that span the image of a matrix A, it is essential to identify the linear combinations of its columns. For matrix A_1, the image is spanned by the vectors v_1 = [1, 1, 1, 1] and v_2 = [1, 2, 3, 4]. For matrix A_2, the goal is to determine a basis for the row space, which can be achieved by reducing the rows to identify leading ones. The resulting vectors that span the image of A_2 are [1, 1] and [1, 2]. Understanding the relationship between the number of vectors and the matrix dimensions is crucial in this process.
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For each matrix A, find vectors that span the image of A. Give as few vectors as possible.

\mathbf{A_1} =<br /> \left[ \begin{array}{cc}<br /> 1 &amp; 1 \\<br /> 1 &amp; 2 \\<br /> 1 &amp; 3 \\<br /> 1 &amp; 4<br /> \end{array} \right]


\mathbf{A_2} =<br /> \left[ \begin{array}{cccc}<br /> 1 &amp; 1 &amp; 1 &amp; 1 \\<br /> 1 &amp; 2 &amp; 3 &amp; 4 \\<br /> \end{array} \right]


My work:

T(\overrightarrow{x})\,=\,A_1\,\overrightarrow{x}

A_1\,\left[ \begin{array}{c}<br /> x_1 \\<br /> x_2 \\<br /> x_3 \\<br /> x_4 <br /> \end{array} \right]\,=\,\left[ \begin{array}{cc}<br /> 1 &amp; 1 \\<br /> 1 &amp; 2 \\<br /> 1 &amp; 3 \\<br /> 1 &amp; 4<br /> \end{array} \right]\,\left[ \begin{array}{c}<br /> x_1 \\<br /> x_2<br /> \end{array} \right]

x_1\,\left[ \begin{array}{c}<br /> 1 \\<br /> 1 \\<br /> 1 \\<br /> 1 <br /> \end{array} \right]\,+\,x_2\,\left[ \begin{array}{c}<br /> 1 \\<br /> 2 \\<br /> 3 \\<br /> 4 <br /> \end{array} \right]

The image of A_1 is the space spanned by

v_1\,=\,\left[ \begin{array}{c}<br /> 1 \\<br /> 1 \\<br /> 1 \\<br /> 1 <br /> \end{array} \right]\,\,and\,\,v_2\,=\,\left[ \begin{array}{c}<br /> 1 \\<br /> 2 \\<br /> 3 \\<br /> 4 <br /> \end{array} \right]

For the second part:

A_2\,\overrightarrow{x}

\left[ \begin{array}{cccc}<br /> 1 &amp; 1 &amp; 1 &amp; 1 \\<br /> 1 &amp; 2 &amp; 3 &amp; 4 \\<br /> \end{array} \right]\,\left[ \begin{array}{c}<br /> x_1 \\<br /> x_2 \\<br /> x_3 \\<br /> x_4 <br /> \end{array} \right]

x_1\,\left[\begin{array}{c}<br /> 1 \\<br /> 1 \\<br /> \end{array}\right]\,+\,x_2\,\left[\begin{array}{c}<br /> 1 \\<br /> 2 \\<br /> \end{array}\right]\,+\,x_3\,\left[\begin{array}{c}<br /> 1 \\<br /> 3 \\<br /> \end{array}\right]\,+\,x_4\,\left[\begin{array}{c}<br /> 1 \\<br /> 4 \\<br /> \end{array}\right]

But now I don't know where to proceed to solve the second part. The B.O.B. says that the answer is

\left[\begin{array}{c}<br /> 1 \\<br /> 1 \\<br /> \end{array}\right],\,\left[\begin{array}{c}<br /> 1 \\<br /> 2 \\<br /> \end{array}\right]

How do I show such?
 
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You are trying to find a basis for the "row space". Treat each row as a vector and reduce. Obviously you have 4 rows, so 4 vectors, but the image is subset of R2 and so can have dimension no larger than 2.

Actually, if the dimension is 2, then (1,0), (0, 1) will work. If 1, anyone of the rows will work.
 
A_1 has four rows, but only two vectors. I am assuming that the number of columns should equal the number of vectors?

Where are you getting the (1, 0) and (0, 1 ) from?

By "dimension", do you mean the number of columns in a matrix, or the number of rows?
 
Leading ones.

Solve for leading ones. you will get something like: [(1,0,-1,-2);(0,1,2,3)]. You can see that the columns with leading ones refer you back to the original matrix, which gives you the answer that the BOB had. Hope that helps.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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