Linear Algebra / Gaussian Elimination

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SUMMARY

The discussion focuses on solving for coefficients a, b, c, and d in the equation of a circle represented as ax² + ay² + bx + cy + d = 0, using Gaussian elimination. Participants emphasize substituting the given points (-4,5), (-2,7), and (4,-3) into the equation to derive three linear equations. Due to the nature of the problem, a unique solution is unattainable, necessitating the expression of three variables in terms of one. The conversation highlights the expectation of encountering complex fractions in the Row Echelon Form during the elimination process.

PREREQUISITES
  • Understanding of Gaussian elimination techniques
  • Familiarity with linear equations and systems of equations
  • Knowledge of conic sections, specifically circles
  • Basic algebraic manipulation skills
NEXT STEPS
  • Practice Gaussian elimination with different sets of linear equations
  • Explore the derivation of conic sections from general equations
  • Learn about Row Echelon Form and its applications in solving systems
  • Investigate the implications of non-unique solutions in linear algebra
USEFUL FOR

Students studying linear algebra, mathematics educators, and anyone interested in solving systems of equations involving conic sections.

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Homework Statement



Find coefficients a,b,c and d so that the curve of a circle in an xy plane, with points (-4,5), (-2,7) and (4,-3), is given by the equation ax2 + ay2 + bx + cy + d = 0.

Not even sure where to start. Can anyone help me with this?
 
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Use Gaussian elimination. Substitute the x and y values for each point into the equation and get three linear equations for a, b, c and d. But you don't have enough equations to get a unique solution. You'll have to express three of those variables in terms of another. You've got to expect this. (ax^2 + ay^2 + bx + cy + d)/k=0 is the same circle for any nonzero k.
 
Thanks Dick. I guess I'll get some big ugly fractions in my Row Echelon Form, correct? So far I've got numbers over 53 in the 1st row, over 65 in the 2nd row, and the 3rd row looks like it'll be a 4 digit denominator.
 
page13 said:
Thanks Dick. I guess I'll get some big ugly fractions in my Row Echelon Form, correct? So far I've got numbers over 53 in the 1st row, over 65 in the 2nd row, and the 3rd row looks like it'll be a 4 digit denominator.

Probably. I didn't actually work it out, but it doesn't look like it was set up to come out nice. Sounds like you are the right track though.
 

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