Linear Algebra Help - Pythagorem Theorem

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
eunhye732
Messages
11
Reaction score
0
I have been trying to figure this out but can't. I even went to the tutorial but the lady kept mumbling so it was obvious that she didn't really know how to do it either. So I really hope someone could help me. The only thing he told me was to look at the pythagorem theorem. Thanks
 

Attachments

  • scan0002.jpg
    scan0002.jpg
    14.3 KB · Views: 481
Physics news on Phys.org
The question is to show that norm(v over norm(v))= 1 for v a vector.
That is, that
[tex]\left|\left|\frac{v}{\left|\left|v\right|\right|}\right|\right|= 1[/tex]
eunhye732, one of the things you certainly should have learned about the "norm" is that ||av||= |a| ||v|| for a any number and v a vector. In particular, if a is a positive number then ||av||= a ||v||.
Think about that with a= 1/||v||.
 
Last edited by a moderator:
HallsofIvy said:
The question is to show that norm(v over norm(v))= 1 for v a vector.
That is, that
[tex]\left|\left|\frac{v}{\left|\left|v\left|\left|}\left|\left|= 1[/tex]
eunhye732, one of the things you certainly should have learned about the "norm" is that ||av||= |a| ||v|| for a any number and v a vector. In particular, if a is a positive number then ||av||= a ||v||.
Think about that with a= 1/||v||.

Oh i see how to do it now.
That helped a lot.
Thanks so much!