LINEAR ALGEBRA: image of vectors through other basis

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Homework Help Overview

The discussion revolves around a problem in linear algebra concerning the transformation of vectors through a specified basis in three-dimensional space, specifically using an orthonormal basis and an endomorphism represented by a matrix.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between the orthonormal basis and the canonical basis, questioning the correctness of the original poster's approach to finding the transformation of basis vectors. There is discussion about the linearity of the transformation and how to express vectors in terms of the given basis.

Discussion Status

Some participants have provided hints and guidance without revealing complete solutions. There is an ongoing exploration of the calculations involved in determining the transformed vectors, with some participants expressing uncertainty about the original poster's reasoning.

Contextual Notes

Participants note the importance of adhering to homework guidelines, which restrict the provision of complete solutions and encourage hints instead. There is also mention of differing results for the transformation of specific vectors, indicating a need for careful verification of calculations.

Felafel
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Homework Statement



In ##E^3##, given the orthonormal basis B, made of the following vectors ## v_1=\frac{1}{\sqrt{2}}(1,1,0); v_2=\frac{1}{\sqrt{2}}(1,-1,0); v_3=(0,0,1)##
and the endomorphism ##\phi : E^3 \to E^3## such that ##M^{B,B}_{\phi}##=A where
(1 0 0)
(0 2 0) = A
(0 0 0)
find:
##\phi(e_1), \phi(e_2), \phi(e_3)## written with respect to the canonical basis
(where e1, e2, e3 are vector of the canonical basis ##\mathcal{E}##)


The Attempt at a Solution



here is what I thought, but having no solutions i don't know if it is correct:

I write the vectors of the canonical basis as combination of the vectors of B, also obtaining the ##M^{B,\mathcal{E}}##:

(1,0,0)=##a_{11} \cdot \frac{1}{\sqrt{2}}(1,1,0)+ a_{21} \cdot \frac{1}{\sqrt{2}}(1,-1,0)+ a_{31} \cdot (0,0,1)##

(0,1,0)=##a_{12} \cdot \frac{1}{\sqrt{2}}(1,1,0)+ a_{22} \cdot \frac{1}{\sqrt{2}}(1,-1,0)+ a_{32} \cdot (0,0,1)##

(0,0,1)=##a_{13} \cdot \frac{1}{\sqrt{2}}(1,1,0)+ a_{23} \cdot \frac{1}{\sqrt{2}}(1,-1,0)+ a_{33} \cdot (0,0,1)##

getting:

(##\frac{\sqrt{2}}{2}## ##\frac{\sqrt{2}}{2}## 0)
(##\frac{\sqrt{2}}{2}## -##\frac{\sqrt{2}}{2}## 0)= ##M^{B, \mathcal{E}}##
( 0 0 1)

so ##\phi(e_1), \phi(e_2), \phi(e_3)## are the columns of this matrix.
Is it correct?
thank you in advance :)
 
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I haven't thought it all through, but it doesn't look correct to me. I don't see why those columns would contain the ##\mathcal E##-components of the ##\phi(e_i)##. Do you have an argument for it? Also, I think I have calculated ##\phi(e_3)##, and my result is different from yours.

I think the strategy here should be to start with
$$\phi(e_i)=\phi\left( \sum_j M^{B,\mathcal E}_{ji} v_j\right) =\sum_j M^{B,\mathcal E}_{ji}\phi(v_i).$$ Now you just have to compute the ##\phi(v_i)##. (Did I understand your definition of ##M^{B,\mathcal E}## correctly?)
 
i don't think i have understood what you mean :(. could you please do an example of the calculation you have done by using a vector?
 
I don't want to give away too much information. We only give hints here, not complete solutions. But I can of course explain what I did there. I just rewrote ##e_i## as a linear combination of the ##v_i## and then I used that ##\phi## is linear.

The ##\phi(v_i)## are easy to calculate, since you've been given the matrix representation of ##\phi## in the ##\{v_i\}## basis.
 
thank you :) solved it!
 

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