Linear Algebra, Matrix Inverse Proof

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SUMMARY

The discussion focuses on proving the invertibility of the expression (A^-1 + 2B^-1) given that matrices A, B, and 2A + B are invertible. Participants explore methods to express the inverse of (A^-1 + 2B^-1) in terms of A, B, and (2A + B)^-1. Key strategies include leveraging the properties of matrix multiplication and the Binomial Inverse Theorem. The conversation emphasizes the importance of understanding matrix operations to tackle the problem effectively.

PREREQUISITES
  • Understanding of matrix operations, specifically matrix addition and multiplication.
  • Knowledge of matrix invertibility and conditions for a matrix to be invertible.
  • Familiarity with the Binomial Inverse Theorem and its application in linear algebra.
  • Proficiency in manipulating expressions involving matrices, including distributive properties.
NEXT STEPS
  • Study the properties of matrix inverses, focusing on conditions for invertibility.
  • Learn how to apply the Binomial Inverse Theorem in various contexts within linear algebra.
  • Practice problems involving the manipulation of matrix expressions and their inverses.
  • Explore advanced topics in linear algebra, such as eigenvalues and eigenvectors, to deepen understanding.
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Students and professionals in mathematics, particularly those studying linear algebra, as well as educators seeking to enhance their understanding of matrix theory and its applications.

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Homework Statement


Let A,B and and 2A + B be invertible n x n matrices. Show that (A^-1 + 2B^-1) is also invertible and express (A^-1 + 2B^-1)^-1 in terms of A, B and (2A+B)^-1

The Attempt at a Solution


I'm not exactly sure how to tackle this problem, i know that for a matrix to be invertible, we have to be able to multiply (both pre and post multiply it) by some other matrix so that their product gives the identity, however, in this case, I'm completely lost as to what to due to the sum of the matrices inside the brackets. Any hints on suggests? Can i let C = the sum of A+2B say to simplify matters? but even if i do that I am not sure how to proceed.

I've also been reading on this thing called 'Binomial Inverse Theorum' but again, I am not to sure if I am barking up the wrong tree or how to apply it to this case.

Thanks for any and all help
 
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As some attempted working, If i multiply A(A^-1 +2B^-1)2B does that give me I? Essentially what I am finding most confusing is how to deal with the terms in the brackets.
 
the distributive law holds for matrices;

C(A+B)=CA+CB

so to expand

(A+B)(C+D),

first you expand the left bracket:

A(C+D)+B(C+D)

and then you do the right brackets similarly.
 

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