Linear Algebra: Solid Enclosed

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Homework Help Overview

The problem involves finding the mass of a solid enclosed by a paraboloid defined by the equation z = x² + y² and a plane at z = 9, with a density function given by f(x,y,z) = x². The context is within the subject area of multivariable calculus, specifically dealing with triple integrals in cylindrical coordinates.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the limits of integration for the triple integral, questioning the setup of the cylindrical coordinates and the dependence of r on z. There are attempts to express the density function in cylindrical coordinates and set up the integral accordingly.

Discussion Status

There is an ongoing examination of the limits of integration, with some participants suggesting corrections to the initial attempts. Guidance has been offered regarding the relationship between r and z, indicating a productive direction in clarifying the setup of the problem.

Contextual Notes

Participants note that the limits for r should depend on the paraboloid, and there is a discussion about the implications of integrating in cylindrical coordinates. The conversation reflects a need to reconcile the geometric interpretation of the solid with the mathematical formulation.

Stan12
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Homework Statement


Let E be the solid enclosed by the paraboloid z = x2 + y2 and the plane z = 9. Suppose the density of this solid at any point (x,y,z) is given by f(x,y,z) = x2.


Homework Equations


x2 + y2 = r2 = 9; r = 3
∫∫∫E x2



The Attempt at a Solution


The limit of z is given z=9, found r = 3, and θ=2∏

x = rcosθ
y = rsinθ
z = z

∫∫∫ r2cos2θ r dzdrdθ

I got 729∏ / 4 as final answer
 
Last edited:
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Stan12 said:

Homework Statement


Let E be the solid enclosed by the paraboloid z = x2 + y2 and the plane z = 9. Suppose the density of this solid at any point (x,y,z) is given by f(x,y,z) = x2.


Homework Equations


x2 + y2 = r2 = 9; r = 3
∫∫∫E x2



The Attempt at a Solution


The limit of z is given z=9, found r = 3, and θ=2∏

x = rcosθ
y = rsinθ
z = z

∫∫∫ r2cos2θ r dzdrdθ

I got 729∏ / 4 as final answer

I don't think that is correct. Show us your limits and your work.
 
z = x2 + y2 and plane z = 9

I set x2 + y2 = r2
and found that 0<r<3
and 0<z<9 since it's given
and 0<θ<2∏

x=rcosθ in cylindrical coord.

f(x,y,z) = x2 --> x2 in cylindrical coord. = (rcosθ)2

I set the function under a triple integral with restriction above

so I got ∫∫∫ (rcos)2 rdrdzdθ
 
∫∫z r3 cos2θ drdθ

9 ∫ r4/4 cos2θ dθ
(9 * 34)/4 ∫cos2θ dθ
(9 * 34)/4 ∫(cos2θ + 1)/2 dθ = (9 * 34)/4 *1/2 [ (sin2θ)/2 + θ ] 0<θ<2∏

I got (9 * 34 * 2∏)/8 = 729∏/4
 
LCKurtz said:
I don't think that is correct. Show us your limits and your work.

Stan12 said:
z = x2 + y2 and plane z = 9

I set x2 + y2 = r2
and found that 0<r<3
and 0<z<9 since it's given
and 0<θ<2∏

x=rcosθ in cylindrical coord.

f(x,y,z) = x2 --> x2 in cylindrical coord. = (rcosθ)2

I set the function under a triple integral with restriction above

so I got ∫∫∫ (rcos)2 rdrdzdθ

Those are not the correct limits. If you are integrating dr first, the value of r depends on z. Your limits describe a cylinder of radius 3 and height 9, which is not what you have. The side of your object is a paraboloid. r goes from r=0 to the r on the paraboloid.
 
So the limits to r is from 0 to r = √x2 + y2 or r = √z
and limit of z is from 0 to 9 ? since the paraboloid begins at 0 and enclosed by the plane at z = 9

∫∫∫ r2cos2θ rdrdzdθ
 
Stan12 said:
So the limits to r is from 0 to r = √x2 + y2 or r = √z
and limit of z is from 0 to 9 ? since the paraboloid begins at 0 and enclosed by the plane at z = 9

∫∫∫ r2cos2θ rdrdzdθ

Yes.
 

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