Linear Algebra System Solution: (x,y,z) = (a,b,a), Non-Integer a + b Calculation

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SUMMARY

The forum discussion centers on solving the linear algebra system defined by the equations ax + ay - z = 1, x - ay - az = -1, and ax - y + az = 1, with the solution (x,y,z) = (a,b,a). The challenge presented is to determine the numerical value of a + b when a is not an integer. The user initially attempts to substitute (a,b,a) into the equations but encounters confusion regarding the implications of a being non-integer. A correction is noted regarding the arrangement of terms in the equations.

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  • Study the method of solving systems of linear equations using substitution.
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jcharky
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The solution of the system

ax + ay - z = 1
x - ay - az = -1
ax - y + az = 1

is (x,y,z) = (a,b,a). If a is not an integer, what is the numberical value of a + b.

So I guess i should plug in (a,b,a) for (x,y,z) first..

a^2 + ab - a = 1
a - ab + a^2 = -1
a^2 - b - a^2 = 1

I am not sure how to solve for a + b though and I am not sure how part that a is not an integer comes into play can someone help?
 
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Welcome to PF!

Hi jcharky ! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

Your second and third equations have a2 the wrong way round. :redface:
 

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