Linear Approximation: Find & Use for f(2.28,8.22)

Click For Summary

Homework Help Overview

The discussion revolves around finding the linear approximation of the function f(x,y) = 3 sqrt((x y)/4) at the point (2,8,6) and using it to approximate f(2.28,8.22). Participants are exploring the derivatives needed for this approximation.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to derive the necessary partial derivatives fx(x,y) and fy(x,y) but expresses uncertainty about their correctness. Other participants suggest starting with a simpler function to clarify the derivative process.

Discussion Status

Some participants are providing guidance on the derivative calculations and discussing the concept of linear approximation in relation to tangent lines. There is an ongoing exploration of the correct approach to finding the derivatives.

Contextual Notes

There appears to be confusion regarding the derivatives of the function, and participants are questioning the original poster's calculations. The discussion is framed within the context of homework help, indicating that participants are adhering to guidelines about not providing complete solutions.

andyk23
Messages
26
Reaction score
0
Find the linear approximation to the equation f(x,y) = 3 sqrt((x y)/4) at the point (2,8,6), and use it to approximate f(2.28,8.22). I know you take the derivative of fx(x,y) and fy(x,y), I think I'm taking the derivative wrong. Then after that you put x and y in the equation and solve for fx(2,8) and fy(2,8). Then take f(a,b)+fx(a,b)(x-a)+fy(a,b)(y-b). For fx(x,y) I'm coming up with .75(y/4) and for fy(x,y) I'm getting .75(x/4)
 
Physics news on Phys.org
Your derivatives are indeed wrong. Let's start with a simpler function of just one variable.

g(x) = 3 \sqrt{x / 4}What is g'(x)?
 
g(x)=3(x/4)^-.5
g'(x)= [3(x)^-.5]/4
 
Want to know an easy way to derive a linear approximation equation? Well, I'll give you some intuition: it's basically the same thing as the tangent line equation in so many words.
 
L(x)= f(x) + f'(a)(x-a)

(2.8,6) is the point...and so on
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K