Linear Equations: how to deduce this inequality is true?

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SUMMARY

The discussion centers on deducing the inequality $$\frac{3}{x+2}<\frac{13}{12}<\frac{3}{x}$$ as part of solving the equation $$\frac{1}{x}+\frac{1}{x+1}+\frac{1}{x+2}=\frac{13}{12}$$. The conclusion drawn is that the only positive integer solution for x is 2, as x=1 does not satisfy the equation. The reasoning involves comparing the largest and smallest fractions derived from the equation, leading to the inequalities that bound x.

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yucheng
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Homework Statement
The number of positive integers x satisfying the equation
Relevant Equations
$$\frac{1}{x}+\frac{1}{x+1}+\frac{1}{x+2}=\frac{13}{12}$$
The solution from my book:

From $$\frac{3}{x+2}<\frac{13}{12}<\frac{3}{x} \tag1$$

It follows that ##13x<36<13(x+2)##

x<3, i.e. x = 1 or 2. By checking, x=1 is not the solution and x = 2 satisfies the equation.

However, how does the author deduce (1)?
 
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yucheng said:
Homework Statement:: The number of positive integers x satisfying the equation
Relevant Equations:: $$\frac{1}{x}+\frac{1}{x+1}+\frac{1}{x+2}=\frac{13}{12}$$

The solution from my book:

From $$\frac{3}{x+2}<\frac{13}{12}<\frac{3}{x} \tag1$$

It follows that ##13x<36<13(x+2)##

x<3, i.e. x = 1 or 2. By checking, x=1 is not the solution and x = 2 satisfies the equation.

However, how does the author deduce (1)?
Of the three numbers, the largest is ##\frac 1 x## and the smallest is ##\frac 1{x + 2}##. Three times the largest will be larger than 13/12 and three times the smallest will be less than 13/12.
 
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