Linear maps (rank and nullity)

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Homework Help Overview

The problem involves a linear map T from ℝm to ℝn and asks for the nullity given the rank of the map. Participants are exploring the relationship between rank, nullity, and the dimensions of the vector spaces involved.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the definitions of rank and nullity, with one noting that nullity can be calculated as total columns minus rank. There is uncertainty regarding the total number of columns in the context of the linear map.

Discussion Status

The discussion is ongoing, with participants questioning the total number of columns in the matrix representing the linear map. Some have referenced the rank-nullity theorem, indicating a potential direction for understanding the relationship between rank, nullity, and the dimensions of the spaces involved.

Contextual Notes

There is ambiguity regarding the total number of columns in the linear transformation, as the problem does not specify the dimensions of the matrix beyond the rank. Participants are considering the implications of this missing information.

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Homework Statement


A linear map T: ℝ^{m}-> R^{n} has rank k. State the value of the nullity of T.

The Attempt at a Solution



I know that rank would be the number of leading columns in a reduced form and the nullity would simply be the number of non-leading columns, or total columns - rank.

As we are not given how many different vectors are in the matrix, I'm not too sure how to give a value.
 
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NewtonianAlch said:
nullity would simply be [...] total columns - rank.

The rank is given.
What is the total number of columns for a map \mathbb{R}^m \to \mathbb{R}^n?
 
I'm inclined to say m, but I'm not entirely sure. So m - k? Considering that's the starting space if you will.
 
The "rank-nullity theorem" which, if you were given this problem, you are probably expected to know, says that if A is a linear transformation from a vector space of degree m to a vectoer space of degree n then rank(A)+ nullity(A)= m.
 
NewtonianAlch said:
I'm inclined to say m, but I'm not entirely sure. So m - k? Considering that's the starting space if you will.

If it's a map from \mathbb{R}^m to \mathbb{R}^n, that means that you should be able to multiply the matrix with a vector with m components, and this should give a vector with n components. If you think about the way matrix multiplication works, does the number of columns need to be m or n?
 

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