Linear momentum acting on a bullet

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SUMMARY

The discussion centers on calculating the total linear impulse acting on a bullet with a mass of 0.016 kg and a variable force defined by the equation f = 7000 N - 2.2 x 10^6 N/s * t. The bullet exits the gun at a velocity of 800 km/h. The participants derive two potential time values for the bullet's exit: 0.000633 seconds and 0.0025 seconds. The conversation emphasizes the necessity of integrating the force function over time to accurately determine the impulse, rather than simply multiplying force by time due to the non-constant nature of the force.

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I recently had a test question that gave a force acting on a bullet. The bullets mass is 0.016KG, and the force acting on the bullet is f=7000N-2.2*10^6N/s*t. The bullet is traveling 800 k/h when it leaves the gun

It asked to find the total linear impulse on the bullet, and then how much time it took to leave the gun.

[tex]L1+IMP=L2[/tex]
L1 is zero since zero initial velocity

[tex]f*t=m*vf[/tex]

this gives a quadratic only unknown is t

how do I know which root is correct?

BTW the two I get are 0.000633 s and 0.0025 s
 
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Once you have the total impulse, don't you want to just integrate f(t)dt and set that equal to the total impulse? You can't just take force times time. The force isn't constant.
 

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