Linear Momentum Block and Spring Problem

Click For Summary
A 0.500-kg block attached to a spring with a force constant of 23.0 N/m is struck by a 5.60×10^-2 kg wad of putty moving at 2.00 m/s, causing the two to stick together. The momentum conservation principle is applied to find the final velocity after the collision. Initial kinetic energy calculations for the putty are made, but the attempt to equate this to potential energy in the spring leads to confusion. The user initially struggles with the problem but eventually finds the correct solution. The discussion highlights key concepts of momentum and energy conservation in a spring-block system.
shaggyace
Messages
11
Reaction score
0

Homework Statement



A 0.500-kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 23.0 N/m. The block rests on a frictionless surface. A 5.60×10^-2 kg wad of putty is thrown horizontally at the block, hitting it with a speed of 2.00 m/s and sticking.

Homework Equations



p=mv

KE=0.5 mv^2

PE=0.5 kx^2

vf= (m1V1,i + m2v2,i)/m1+m2


The Attempt at a Solution



I tried finding the kinetic energy of the wad of putty as it hit the spring and I got 0.112. I then used this as the PE of the spring and solved for x in the PE equation getting 0.099 m. I know that this is wrong however. I just don't know how to attack this problem.
 
Physics news on Phys.org
Never mind everyone , I figured it out :)
 

Similar threads

Replies
7
Views
2K
Replies
17
Views
2K
Replies
24
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
13
Views
3K
  • · Replies 31 ·
2
Replies
31
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K