Linear Simultaneous Eqns - Gauss Elim Problem

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Homework Help Overview

The discussion revolves around solving a problem involving linear simultaneous equations, specifically focusing on the use of Gaussian elimination and properties of symmetric matrices. Participants are exploring methods to approach the problem and the implications of matrix characteristics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the potential of using row echelon form for solving the equations and question whether alternative methods might be more effective. There is also exploration of the significance of the matrix being symmetric and its implications for finding the inverse.

Discussion Status

Some participants have provided insights into the relationship between the matrix and its inverse, particularly in the context of symmetric matrices. However, there remains uncertainty regarding the application of these concepts to solve for the variables involved.

Contextual Notes

The problem involves a symmetric square matrix, and participants are considering the conditions under which it is invertible and how that affects the solution process. There is an emphasis on understanding the notation and relationships between matrices and their inverses.

Fjolvar
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Hello, I'm stuck on a simultaneous eqns problem. From what I can see it seems the easiest way would be to get the matrix into row echelon form, but I'm not sure if another way would be better. I can see a pattern here but not sure what it means. I attached the problem to the page. Any help would be greatly appreciated.
 

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Fjolvar said:
Hello, I'm stuck on a simultaneous eqns problem. From what I can see it seems the easiest way would be to get the matrix into row echelon form, but I'm not sure if another way would be better. I can see a pattern here but not sure what it means. I attached the problem to the page. Any help would be greatly appreciated.

It is a symmetric square matrix, so if it is invertible it satisfies A-1AT = I.

Take a look here, http://en.wikipedia.org/wiki/Symmetric_matrix.
 
Interesting, how would I use this to solve for the variables X1, X2, X3.. etc?
 
Fjolvar said:
Interesting, how would I use this to solve for the variables X1, X2, X3.. etc?

So, what you really have is [A|B], where B is the column vector of solutions, right? So when you multiply by the matrix you have by its inverse what you really get is [I|A-1B]. Remember when you right it in the form [A|B], it is really just shorthand saying Ax = B. When A is invertible, you have x = A-1B. Does that make sense?
 
I do understand how to find X by taking the inverse of A and multiplying by B, however I'm still not quite sure of the significance of this matrix being symmetric. So A = A transpose, does that help us in finding the inverse of A?
 

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