Linear Subspace of R^n: Arithmetic Progressions Verification

  • Thread starter Thread starter KaiserBrandon
  • Start date Start date
  • Tags Tags
    Linear Subspace
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
KaiserBrandon
Messages
51
Reaction score
0

Homework Statement



Is the set of all vectors in R^n whose components form an arithmetic progression a linear subspace of R^n?

Homework Equations



none

The Attempt at a Solution



I basically need one thing verified: would (0,0,0,...,0) be considered an arithmetic progression. The definition says that an arithmetic progression is one where the difference between any two consecutive members of the sequence is constant. Since 0-0=0, it would seem like it is an arithmetic sequence, however, is there a condition that the difference must be non-zero? If not, then (1,1,...,1), (2,2,...,2), etc. would all be arithmetic progressions, and that doesn't seem right to me.
 
Physics news on Phys.org
alright, so in that case it is a linear subspace since it meets the three requirements to be a linear subspace. Thanks.