Linear transformation, basis of the image

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Homework Help Overview

The problem involves demonstrating that a specific integral transformation, defined on polynomial functions, is an injective linear transformation. Participants are tasked with determining a basis for the image of this transformation and finding the corresponding matrix representation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the properties of the transformation, including linearity and injectivity, by examining specific polynomial forms. There are attempts to identify a suitable basis for the polynomial space and to understand how to compute the image of this basis under the transformation.

Discussion Status

Some participants have made progress in establishing the linearity of the transformation and are exploring injectivity. There is ongoing discussion about identifying an appropriate basis for the polynomial space and how to compute the image of this basis. Confusion remains regarding the notation and the matrix representation of the transformation.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the amount of direct assistance they can provide to one another. There is a focus on understanding the transformation's properties without providing complete solutions.

Chris1557
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Homework Statement


From Calculus we know that, for any polynomial function f : R -> R of degree <= n, the function
I(f) : R -> R, s -> ∫0s f(u) du, is a polynomial function of degree <= n + 1.

Show that the map
I : Pn -> Pn+1; f -> I(f),
is an injective linear transformation, determine a basis of the image of I and fi nd the matrix
M in M(n+2)x(n+1)(R) that represents I with respect to the basis 1,t,...,tn of Pn and the basis 1,t,...,tn+1 of Pn+1.

Homework Equations



The Attempt at a Solution


I found a topic involving setting f(x) = anxn + an-1xn-1 + an-2xn-2 + ... + a1x + a0, and g(x) = bnxn + bn-1xn-1 + bn-2xn-2 + ... + b1x + b0.
Then show that L(f + g) = L(f) + L(g) and that aL(f) = L(ax).

That seems ok, but I have no idea how to determine a basis of the image and I am confused on what the final part in notating and what to do.

Thanks.
 
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Chris1557 said:
I found a topic involving setting f(x) = anxn + an-1xn-1 + an-2xn-2 + ... + a1x + a0, and g(x) = bnxn + bn-1xn-1 + bn-2xn-2 + ... + b1x + b0.
Then show that L(f + g) = L(f) + L(g) and that aL(f) = L(ax).

That's a very good start. This will show that we are dealing with a linear transformation.

That seems ok, but I have no idea how to determine a basis of the image and I am confused on what the final part in notating and what to do.

Let's first determine injectivity. For this, we take a basis of Pn (can you find an easy basis for this?). Take the image of this basis under I and determine whether this image is linear dependent. If so, the function is injective, and behold: the image of the basis is (in that case) a basis for the image!
 
micromass said:
Let's first determine injectivity. For this, we take a basis of Pn (can you find an easy basis for this?). Take the image of this basis under I and determine whether this image is linear dependent. If so, the function is injective, and behold: the image of the basis is (in that case) a basis for the image!

For the easy basis of Pn can we just use xn, xn-1,..., x, 1

How do we take the image of the basis under I?

The matrix part is also confusing me.
 
Just calculate I(xn),...,I(x),I(1). This should be an easy calculation...
 

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