Linear transformation, basis of the image

Chris1557
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Homework Statement


From Calculus we know that, for any polynomial function f : R -> R of degree <= n, the function
I(f) : R -> R, s -> ∫0s f(u) du, is a polynomial function of degree <= n + 1.

Show that the map
I : Pn -> Pn+1; f -> I(f),
is an injective linear transformation, determine a basis of the image of I and fi nd the matrix
M in M(n+2)x(n+1)(R) that represents I with respect to the basis 1,t,...,tn of Pn and the basis 1,t,...,tn+1 of Pn+1.

Homework Equations



The Attempt at a Solution


I found a topic involving setting f(x) = anxn + an-1xn-1 + an-2xn-2 + ... + a1x + a0, and g(x) = bnxn + bn-1xn-1 + bn-2xn-2 + ... + b1x + b0.
Then show that L(f + g) = L(f) + L(g) and that aL(f) = L(ax).

That seems ok, but I have no idea how to determine a basis of the image and I am confused on what the final part in notating and what to do.

Thanks.
 
on Phys.org
Chris1557 said:
I found a topic involving setting f(x) = anxn + an-1xn-1 + an-2xn-2 + ... + a1x + a0, and g(x) = bnxn + bn-1xn-1 + bn-2xn-2 + ... + b1x + b0.
Then show that L(f + g) = L(f) + L(g) and that aL(f) = L(ax).

That's a very good start. This will show that we are dealing with a linear transformation.

That seems ok, but I have no idea how to determine a basis of the image and I am confused on what the final part in notating and what to do.

Let's first determine injectivity. For this, we take a basis of Pn (can you find an easy basis for this?). Take the image of this basis under I and determine whether this image is linear dependent. If so, the function is injective, and behold: the image of the basis is (in that case) a basis for the image!
 
micromass said:
Let's first determine injectivity. For this, we take a basis of Pn (can you find an easy basis for this?). Take the image of this basis under I and determine whether this image is linear dependent. If so, the function is injective, and behold: the image of the basis is (in that case) a basis for the image!

For the easy basis of Pn can we just use xn, xn-1,..., x, 1

How do we take the image of the basis under I?

The matrix part is also confusing me.
 
Just calculate I(xn),...,I(x),I(1). This should be an easy calculation...
 

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