Linear transformation defined by T(a + bx) = (a, a+b)

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SUMMARY

The linear transformation T: P_1(R) --> R^2 is defined by T(a + bx) = (a, a+b). The inverse transformation T-1: R^2 --> P_1(R) is given by T-1(c, d) = c + (d-c)x, which is also linear. To verify the properties of these transformations, one must understand the relationships between the components of the ordered pairs in R^2 and the polynomial expressions in P_1(R). The discussion emphasizes the importance of recognizing how the components c and d relate to the original polynomial coefficients a and b.

PREREQUISITES
  • Understanding of linear transformations in vector spaces
  • Familiarity with polynomial spaces, specifically P_1(R)
  • Knowledge of inverse functions and their properties
  • Basic concepts of ordered pairs and their representation in R^2
NEXT STEPS
  • Study the properties of linear transformations in detail
  • Explore the structure and properties of polynomial spaces, particularly P_1(R)
  • Learn about the verification of linearity for transformations and their inverses
  • Investigate examples of linear transformations and their inverses in higher dimensions
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Mathematicians, students studying linear algebra, and anyone interested in understanding linear transformations and polynomial mappings.

jeff1evesque
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Example
Let T: [tex]P_1(R) --> R^2[/tex] be the linear transformation defined by T(a + bx) = (a, a+b).
The reader can verify directly that T-1: [tex]R^2 --> P_1(R)[/tex] is defined by T-1(c, d) = c + (d-c)x. Observe that T-1 is also linear.

I am reading my text and it kind of makes sense, but I have no clue how to verify what has been said above. It make sense to reverse everything, and because after the reversal since the inverse doesn't have the element c for the second element in the order pair for [tex]R^2[/tex] then we subtract it from the image of T-1? But I don't feel comfortable with the concept (of this reversal-and subtraction), and I don't know how to verify what has been said.
 
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If (c, d) is an element of the range of T (and thus the domain of T-1), then c = a and d = a+b for some element (a + bx) in the domain of T. This should start you in the right direction.
 


slider142 said:
If (c, d) is an element of the range of T (and thus the domain of T-1), then c = a and d = a+b for some element (a + bx) in the domain of T. This should start you in the right direction.

Thank you,

JL
 

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