Linear Transformation R2->R3 with 'zero' vector

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SUMMARY

The transformation T(X,Y) = (X,Y,1) is confirmed as a linear transformation from R² to R³. This conclusion is reached by demonstrating that T(cX + Y) = cT(X) + T(Y) holds true for any vectors X and Y in R². The proof involves substituting the zero vector, resulting in T(0,0) = (0,0,1), which aligns with the properties of linear transformations. Thus, T(X,Y) maintains linearity in its operation.

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Homework Statement


Is T(X,Y)->(X,Y,1) a linear transformation? where X and Y are defined R2 column vectors.

Homework Equations


Attempt to prove T(cX+Y)=cT(X)+T(Y)
Consider T(cx1+y1,cx2+y2)->(cx1+y1,cx2+y2,1)

The Attempt at a Solution


RS=cT(x1,y1)+T(x2,y2)->c(x1,y1,1)+(x2,y2,1)
=(cx1+y1,cx2+y2,1)+(0,0,c)
=(cx1+y1,cx2+y2,1)+c(0,0,1)
The 'zero' vector: T(0,0)->(0,0,1)
therefore T(cx1+y1,cx2+y2)->(cx1+y1,cx2+y2,1)
and T(X,Y)->(X,Y,1) is a linear transformation.
 
Last edited:
Physics news on Phys.org
zero vectors are only of the form (0,0) and (0,0,0).
 

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