Linking gradient of IV graph and resistance

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The discussion centers on the relationship between the gradient of a current-voltage graph and resistance, specifically how the reciprocal of the gradient at a point represents resistance. The author encountered a penalty on an AS level physics exam for linking the gradient to resistance, prompting questions about the mark scheme's validity. Participants suggest that the mark scheme may contain errors, particularly regarding the wording and the interpretation of the relationship between current and voltage. They argue that omitting the gradient reference undermines the completeness of the allowed answers. Clarity on the distinction between the rates of change of current and voltage is also emphasized.
MBBphys
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Homework Statement


If I have a current-voltage (y-x) graph for a resistor, I could argue that the reciprocal of the gradient at a point is equal to the resistance of that resistor at that pd across it.

However, on a markscheme for an AS level physics paper, they penalised linking gradient to resistance in any way whatsoever. Why is that?

Thanks in advance for any help!

Homework Equations


V=IR

The Attempt at a Solution


N/A
 
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MBBphys said:

Homework Statement


If I have a current-voltage (y-x) graph for a resistor, I could argue that the reciprocal of the gradient at a point is equal to the resistance of that resistor at that pd across it.

However, on a markscheme for an AS level physics paper, they penalised linking gradient to resistance in any way whatsoever. Why is that?

Thanks in advance for any help!

Homework Equations


V=IR

The Attempt at a Solution


N/A
It might help to quote the whole question verbatim. E.g. is it possible there is inductance involved here?
 
haruspex said:
It might help to quote the whole question verbatim. E.g. is it possible there is inductance involved here?
It's question 1 part c) of the document attached; thanks!
 

Attachments

MBBphys said:
It's question 1 part c) of the document attached; thanks!
And the markscheme's attached as well if you wish to see
 

Attachments

MBBphys said:
And the markscheme's attached as well if you wish to see
The actual section of the markscheme, with the comment about not accepting link between gradient and resistance highlighted. Thanks :)
 

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I believe the author of the mark scheme stuffed up in at least two ways.
In the "do not allow" there is a crucial word missing. It should say "do not allow either of the first two marking points if no reference made linking gradient and R value". The point is that the two options being allowed as variants to the preferred answer are incomplete unless you mention the gradient as the way to determine R.
This is also a blunder: "qualification: I increases faster than V"
Since I and V are dimensionally different, it does not mean anything to say that one increases faster than the other. It should say "the rate of increase of I with respect to V increases".
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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