List the elements of the field F = F3[x] / < x2 + 1 >

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The discussion focuses on the field F = F3[x] / < x^2 + 1 >, where F3 represents the finite field with three elements. Participants clarify that the elements of this quotient field are represented as equivalence classes of polynomials modulo the ideal generated by x^2 + 1. The nine distinct elements identified are [0], [1], [2], [x], [x+1], [x+2], [2x], [2x+1], and [2x+2]. The polynomial long division is suggested to derive the remainder r(x), which must have a maximum degree of 1, confirming that it can be expressed as r(x) = ax + b for a, b in F3.

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Can someone please explain the deconstruction and elements of this set. I understand it to be..

F3[X] = {f(x)=a(0)+a(1)X+...+a(n)X^n : a(i) in F3]
<x^2+1> = {g(x)(x^2+1): g(x) in F3[x]]

So an element in the quotient should be something like f(x)+<x^2+1>

Yet, research shows there are nine elements:
[0], [1], [2], [x], [x+1], [x+2], [2x], [2x+1], [2x+2]

I just don't see how they are derived.

Thanks!
 
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Write $f(x) = q(x)(x^2 + 1) + r(x)$ using polynomial long division.

What can you say about the maximum degree of $r(x)$?

Show $r(x) + \langle x^2 + 1\rangle = f(x) + \langle x^2 + 1\rangle$.

This entails showing $f(x) - r(x)$ is a multiple of $x^2 + 1$.

Does this give you a hint?
 

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