Locate any bifurcation in 2D system

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SUMMARY

The discussion focuses on identifying bifurcations in the 2D dynamical system defined by the equations x' = ux - y + x^3 and y' = bx - y. The critical points are determined by setting ux - y + x^3 = 0 and y = bx, leading to x = 0 and ±sqrt(b - u). It is established that when b - u < 0, no critical points exist, indicating a lack of bifurcation in that parameter range. The analysis emphasizes the importance of evaluating the eigenvalues of the Jacobian matrix at fixed points to determine bifurcation conditions.

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fwang6
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Homework Statement



bifurcation for the following 2D system:

Homework Equations



x'=ux−y+x^3,y′=bx−y

The Attempt at a Solution


I have got ux−y+x^3=0, y=bx, then x=0 and ±sqrt(b−u).

But I don't how to continue to find the bifurcation?
 
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fwang6 said:

Homework Statement



bifurcation for the following 2D system:

Homework Equations



x'=ux−y+x^3,y′=bx−y

The Attempt at a Solution


I have got ux−y+x^3=0, y=bx, then x=0 and ±sqrt(b−u).

But I don't how to continue to find the bifurcation?

What happens when b - u &lt; 0?

In general, you are looking for values of the parameters for which at least one eigenvalue of <br /> \begin{pmatrix}<br /> \frac{\partial x&#039;}{\partial x} &amp; \frac{\partial x&#039;}{\partial y} \\<br /> \frac{\partial y&#039;}{\partial x} &amp; \frac{\partial y&#039;}{\partial y}<br /> \end{pmatrix}<br /> at a fixed point has zero real part.
 
if b-u<0,no critical points exist.
 

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