- #1

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Is is correct to say that the logarithm of base 2 of a number x, is the same thing as the square root of a number x?

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- #1

- 90

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Is is correct to say that the logarithm of base 2 of a number x, is the same thing as the square root of a number x?

- #2

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Have you tried it on some values? Do you get the same results?

- #3

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To say that ##\log_2{x} = y## you mean that ##x=2^y##, logarithms are just ways of 'inversing' exponentiation (roughly). To say that ##\sqrt{x}=y## you are saying that ##x = y^2##, completely different.

However, there is a neat little tidbit that says that ##\sqrt{x}= e^\frac{\ln{x}}{2}##

- #4

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Ok. But I can say that these 2 expressions are correct?

[itex]\log_{b} x = y[/itex], and [itex]b^y=x[/itex]

[itex]\log_{b} x = y[/itex], and [itex]b^y=x[/itex]

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- #5

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Yes, just the definition of logs.

- #6

Mark44

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The appropriate terminology is that the two equations areOk. But I can say that these 2 expressions are correct?

[itex]\log_{b} x = y[/itex], and [itex]b^y=x[/itex]