Logarithm Questions - Solve Now!

  • Thread starter Thread starter Jouster
  • Start date Start date
  • Tags Tags
    Logarithm
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
Jouster
Messages
5
Reaction score
0
Homework Statement
By changing the base of log[SUB]3a[/SUB]9, express (log3a9)(1+loga3) as a single logarithm to base a. I don't know what to do to simplify the equation further
Relevant Equations
Logarithms
1671093569418.png
 
Last edited:
Physics news on Phys.org
Jouster said:
I don't know what to do to simplify the equation further
Minimize your algebra by applying what you know about logarithms to finish rewriting your first line:
$$\log_{3a}9=\frac{\log_{a}9}{\log_{a}3a}=\frac{\log_{a}3^{2}}{\log_{a}a+\log_{a}3}=\frac{2\log_{a}3}{1+\log_{a}3}$$
 
@Jouster: this is the latest of several threads you've started about logarithms where you have not applied the fundamental principle of logarithms: [itex]\log_a(bc) = \log_a(b) + \log_a(c)[/itex]. You need to get into the habit of applying this principle before asking for help.
 
Also @Jouster -- Please post your math using LaTeX, not in images. See the "LaTeX Guide" link below the Edit window for more information. Thank you.