Logarithmic Help: Solving for z, m & n

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SUMMARY

The discussion focuses on solving logarithmic equations involving approximations of numbers using the base 1.1. The user successfully calculated the first two values using the formula Int( \frac{Log(2)}{Log(1.1)} ) but struggled with finding values for z, m, and n. The key insight shared is to express 2 and 3 as powers of 1.1, specifically 1.1^N and 1.1^M, and to derive z from the relationship 2^x ≈ (1.1^7)^x = 1.1^{7x}.

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Homework Statement



http://img20.imageshack.us/img20/1476/mathproblemi.jpg


Homework Equations



Properties of logs.

The Attempt at a Solution



For the first two I did:

Int( [tex]\frac{Log(2)}{Log(1.1)}[/tex] )

Doing this resulted in the correct answers for the first two boxes. When I try similar techniques to solve for z, m,n I get incorrect answers.

Anyone have tips or suggestions on how to go about finding these?
 
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Your task is to approximate 2 and 3 as 1.1^N and 1.1^M, and solve z from there.
 
If [itex]1.1^7[/itex] is approximately 2 then [itex]2^x[/itex] is approximately [itex](1.1^7)^x= 1.1^{7x}[/itex]. That's the point of this exercise.
 

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