Long problem sum using Newton second law

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving Newton's second law, specifically focusing on a scenario with a car's acceleration, power consumption, and drag forces. Participants are exploring the implications of these concepts in various parts of the problem.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the relationship between force, mass, and acceleration, and how to incorporate drag into the equations. There are attempts to derive differential equations and to understand the conditions for maximum velocity. Questions arise regarding the integration process and the implications of power consumption due to resistance.

Discussion Status

Some participants have provided hints and guidance on how to approach the integration needed for part e, while others are still grappling with the implications of the equations and the conditions set by the problem. Multiple interpretations of the problem's requirements are being explored.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is an acknowledgment of the need to consider drag and power consumption in their calculations.

lauraosborn
Messages
10
Reaction score
0

Homework Statement



Question is here http://postimage.org/image/som50onyv/

Homework Equations


F=MA


The Attempt at a Solution



for a) Power = force * speed

for b) Force = Mass * Acceleration
F = m * dv/dt

for c) for maximum velocity, there must be zero drag

i am stuck at D and E, so can anyone help me?
 
Last edited by a moderator:
Physics news on Phys.org
lauraosborn said:
for b) Force = Mass * Acceleration
F = m * dv/dt
so what's the differential equation you get? Remember to include the drag term.


lauraosborn said:
for c) for maximum velocity, there must be zero drag
If there is no drag, then there is no maximum velocity either (the car will just accelerate forever). You should get the answer to this by solving the differential equation you got from b).
 
For part d you have 80000 watts of power available. Thus the car will accelerate until such time that the power consumed by resistance equals the 80000 watts. So what you have to do now is determine the power consumption due to resistance. From that you can determine the value of k.

Hint: Units show you what to equate.
 
for d) i got that k=50

but am stuck for e) again.
m dv/dt = (80000-50v²)/v

thus m v (dv/dx) = (80000-50v²)/v

and thus 1200v (dv/dx) = (80000-50v²)/v

now do i integrate this to find the answer of part e? I'm kinda lost
 
Just move all v's to one side and x's to the other side, then integrate. The integral is not completely trivial but it's still doable.
 

Similar threads

  • · Replies 42 ·
2
Replies
42
Views
6K
Replies
3
Views
2K
Replies
13
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
44
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K