Long straight wire: Ampere/Biot Savart

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SUMMARY

The discussion focuses on calculating the magnetic field and force acting on an electron moving parallel to a long straight wire carrying a current of 2.0A. Using the Biot-Savart Law, the magnetic field (B) is calculated as 3.95x10-8 T at a distance of 0.01m from the wire. The Lorentz force law is then applied to find the force (F) on the electron, resulting in a magnitude of 6.32x10-22 N, directed radially away from the wire. The direction of the force is contingent on the relative orientations of the current and electron velocity.

PREREQUISITES
  • Understanding of the Biot-Savart Law for magnetic field calculations
  • Familiarity with the Lorentz force law for force on charged particles
  • Knowledge of electromagnetic principles, particularly current-carrying conductors
  • Basic proficiency in vector cross products and their physical implications
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  • Study the derivation and applications of the Biot-Savart Law in electromagnetic theory
  • Explore the implications of the Lorentz force law in different configurations of charged particles
  • Investigate the effects of varying current and distance on magnetic field strength
  • Learn about the right-hand rule for determining the direction of magnetic forces
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Homework Statement


A long straight wire carries a current of 2.0A. An electron moves parallel to it at a distance of 0.01m (I'm assuming id doesn't matter which way it moves) at a velocity, v = 100ms-1
Calculate magnitude & direction of force acting on it.

Homework Equations


B = μ0 L / 2∏r

F = q(v X B)

I know the second is the Lorentz force law & that the first relates to Biot-Savart but for the Biot-Savart I also have,
F12 = μ0/4∏ * I1 δl1 * ( I2 δl2 * rhat 12) / r122

So how does one relate to the other, please.

The Attempt at a Solution



Surely it can't be this easy!

B = μ0 L / 2∏r
B = 4∏x10-7 * 2.0 / 2∏(0.01)
B = 3.95x10-8 T

F = q(v X B)
F = (-1.6x10-19)(100x103)(3.95x10-8
F = -6.32x10-22 N

Magnitude 6.32x10-22 N
Direction (radially) away from wire
 
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Roodles01 said:

Homework Statement


A long straight wire carries a current of 2.0A. An electron moves parallel to it at a distance of 0.01m (I'm assuming id doesn't matter which way it moves) at a velocity, v = 100ms-1
Calculate magnitude & direction of force acting on it.


Surely it can't be this easy!

B = μ0 L / 2∏r
B = 4∏x10-7 * 2.0 / 2∏(0.01)
B = 3.95x10-8 T

F = q(v X B)
F = (-1.6x10-19)(100x103)(3.95x10-8
F = -6.32x10-22 N

Magnitude 6.32x10-22 N
Direction (radially) away from wire

Surely it can!
Except the direction could be towards or away from the wire, depending on the relative direction of v and i and the position of q.

BTW I've never seen L used for current before ...
 
L . . . oops!
 

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