Lorentz Contraction in Supersonic Jets

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Homework Help Overview

The discussion revolves around the concept of Lorentz contraction as it applies to supersonic jets traveling at speeds approximating \(3 \times 10^{-6}c\). Participants are exploring how to calculate the percentage of length contraction experienced by such jets.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the Lorentz contraction formula but arrives at a conclusion that suggests no contraction occurs. Some participants question this conclusion, suggesting that the observed contraction may be negligible rather than nonexistent. There is also discussion about the accuracy of computational tools and methods for calculating gamma.

Discussion Status

Participants are actively engaging with the problem, with some providing alternative suggestions for computational tools and methods to achieve more precise approximations. There is a recognition of the limitations of current calculations and a shared interest in exploring approximations further.

Contextual Notes

There is mention of the original poster's reliance on a TI-83 Plus calculator, which may limit the precision of calculations. The discussion also touches on the implications of approximating gamma to 1 and the resulting interpretations of length contraction.

Benzoate
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Homework Statement


Supersonic jets achieve maximum speeds of about (3 *10^-6)*c.

By what percentage would observe such a jet to be contracted in length?


Homework Equations



The equations for these this problem would be : 1/gamma= L(proper)/Length = 1/sqrt(1-v^2/c^2) ; beta=v/c

The Attempt at a Solution



1/sqrt(1-(v/c)^2)^.5 => 1/sqrt(1-(beta)^2)= 1/sqrt(1-(3e-6)^2)^.5=1=gamma; which leads to gamma=1=L(proper)/Length or L = (1/gamma)*L(proper) = > L=L(proper) leading me to the conclusion that the length of the jet did not contract at all .
 
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You must remember that you have approximated the value of gamma to 1, and that DOES NOT imply that no contraction occurs at all. A better answer would be that the contraction that does occur is too negligible to be observed.

Btw, your formula for length contrction: \frac{1}{\gamma} = \frac{L_o}{L}, is incorrect.
 
neutrino said:
You must remember that you have approximated the value of gamma to 1, and that DOES NOT imply that no contraction occurs at all. A better answer would be that the contraction that does occur is too negligible to be observed.

Btw, your formula for length contrction: \frac{1}{\gamma} = \frac{L_o}{L}, is incorrect.

Oh okay, thank you. the correct formula should be gamma=L(P)/L My TI 83 Plus will only make approximations to 1. is there any other computational tool I can used that will make more precise approximations?
 
Benzoate said:
is there any other computational tool I can used that will make more precise approximations?

I'm sure there must be one, but I'm afraid I don't know any. All calculators I have access to give me 1.
 
You can try a computer algebra program, but I can't guarantee it will work. Your best bet would probably be to use the binomial approximation on gamma.
Taking only the first two terms of the approximation should be exact enough here. If not, the approximation to three terms is:

(1+x)^n = 1 + nx + \frac{n(n-1)}{2!} x^2
 
Last edited:
Benzoate said:
Oh okay, thank you. the correct formula should be gamma=L(P)/L My TI 83 Plus will only make approximations to 1. is there any other computational tool I can used that will make more precise approximations?

for this exp:
1/sqrt(1-(3e-6)^2)^.5?

I got
1.00000000000225
and more precisely
1.00000000000224997798170928355350144490508802983505104210845...:approve:
 

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