Lorentz Contraction with small velocity

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SUMMARY

The discussion focuses on calculating Lorentz contraction for a car traveling at 30 m/s, with a rest length of 5.0 m. The formula used is L = Lr * √(1 - β²), where β is the ratio of the car's velocity to the speed of light. Due to the low velocity, direct calculations yield results close to 1, complicating the evaluation. The solution involves applying the binomial expansion to approximate √(1 - β²) as 1 - (0.5)β², allowing for accurate calculations of contraction in femtometers.

PREREQUISITES
  • Understanding of Lorentz contraction and its formula.
  • Familiarity with the concept of β in relativistic physics.
  • Knowledge of binomial expansion for approximations.
  • Basic grasp of units, specifically femtometers (fm) and their relation to meters.
NEXT STEPS
  • Study the derivation of Lorentz contraction in detail.
  • Learn about the binomial approximation in physics applications.
  • Explore the implications of low-velocity limits in special relativity.
  • Investigate practical examples of Lorentz contraction in high-speed scenarios.
USEFUL FOR

Students of physics, particularly those studying special relativity, educators teaching relativistic concepts, and anyone interested in the mathematical applications of Lorentz contraction.

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Homework Statement


About how many femtometers shorter than its rest length is the length of a car measured in the ground frame if the car is traveling at 30 m/s in that frame? Assume for the sake of argument that the car's rest length is 5.0 m. Remember that 1 fm = 10^-15 m.


Homework Equations


L=Lr*\sqrt{1-\beta^{2}}


The Attempt at a Solution



This is a pretty straight forward Lorentz contraction problem, but all attempts to actually calculate it fail because the velocity is so slow (1*10-7). How can I scale the numbers so solving 1-\beta^{2} doesn't just give me 1?

Thanks for the help.
 
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It takes quite a bit of space (plus a masterful use of latex) to take you through the derivation of the "low velocity" formula. But it ends up as √(1-ß^2) ≈ 1-(0.5)ß^2.

The derivation involves going through a binomial expansion of the original formula. Do you recall doing this in class?
 
Thanks for the reply. We talked about the binomial approximation when we were learning about about the relationship between spacetime and proper time, but I didn't think to apply it in this case.
Thanks for the help.
 

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