Why is the Lorentz Force always perpendicular to velocity?

[JiuBeixin]

As I understand your scenario, the object is moving in frame $S$ not parallel and not perpendicular to the conductor. But the force must be perpenducular to the object's velocity, because in this frame there is only a magnetic field. It may look like this:

View attachment 370316​

Here is the question. Why force is perpenducular to the object's velocity? In frame $S'$ the force is perpenducular to the conductor(in my case)

 

[Sagittarius A-Star]

Here is the question. Why force is perpenducular to the object's velocity? In frame $S'$ the force is perpenducular to the conductor(in my case)

Does my picture in posting #26 describe correctly your case in lab-frame $S$?

 

[A.T.]

In the frame where the test charge is at rest, the EM-force is perpendicular to the (now charged) conductor.

I don't think so, because in frame S′ the conductor is not oriented horizontally.

You might be right here. My
statement above was based on symmetry w.r.t. the normal to the conductor that passes through the test charge. I think it would apply to a long charged rod without a current flowing through it.

But here the negative and positive charges are moving in different directions, so their fields are contracted along different axes, which eventually breaks the above symmetry.

It also makes sense that a boost perpendicular to a force doesn't change its direction.

 

[JiuBeixin]

After thinking about this some, I think you have gotten some good advice when you suggested you wanted to learn more about transformation laws.

Maxwell's equations are fully relativistic. If you know how to properly transform charges and currents (usually expressed as charge density and current density), you can use Maxwell's equations to answer your questions. Judging by your questions, you don't currently even know the name of the Lorentz transform - apologies if I got this wrong).

You give the impression of not having any questions about Maxwell's equations (in the most basic form, two Gauss' laws, Faraday's law, and Ampere's law), but rather about the relativistic aspects.

There's a standardized way of describing the source terms. This is in terms of charge density, which would be coulomb/meter^3, and current density, which would be ampere's per meter^2.

The tool you need to know how these quantities transform when switching from a rest frame to a moving frame is called the Lorentz transform, and that's what you need to research.

It'd also be helpful to know the terms "Lorentz boost", which is the way we describe going from a "stationary" frame of reference to a moving frame of reference, and the term "invariant". Invariants are quantites that don't change when you perform a Lorentz boost, I.e. switch from a stationary frame to a moving frame.

The notable invariant of charge and current doesn't have a catchy name, but is given by the quantity

$$c^2 \rho^2 - |J|^2$$

where c is the speed of light, $\rho$ is the charge density in coulomb's/meter^3, and J is the current density in amperes / m^2.

Note that one point of this is that when we boost a neutral current carrying wire in the direction of current flow, it becomes charged. Which you seem to be aware of.

As far as sources go, the results of a "swarm of particles" are well known, but I don't know of many texts that go through the actual work of analyzing a swarm of particles. Usually they just present the results for the continuum limit.

Thanks! You are right. I really dont know the details about Maxwell's equations and Lorentz transformation, so can you give me some advices that where should I begin my study of these laws, as I am only a beginner.

 

[JiuBeixin]

Does my picture in posting #26 describe correctly your case in lab-frame $S$?

except the force, cause I don't know the force's direction in frame $S$ now.

 

[A.T.]

In frame S′ the force is perpenducular to the conductor(in my case)

That was my initial assumption too, because it's true for a charged rod without a current, but not necessarily for one with a current. See my post #33.

 

[Sagittarius A-Star]

except the force, cause I don't know the force's direction in frame $S$ now.

At @PeterDonis wrote in posting #4, the Lorentz force is
$F = q \left( \vec{E} + \vec{v} \times \vec{B} \right)$.
If there is no electic field in frame $S$, then the cross product remains, which is perpendicular to the velocity and to the magnetic field.

Source:
https://en.wikipedia.org/wiki/Cross_product

 

[pervect]

As I dig into this a bit more, I am becoming a bit confused myself. Purcell famously explains magnetism as due to "length contraction" of the distance between charge, which is what the original poster's question is about. But - length contraction is a second order effect in (normalized) velocity $\beta$, and magnetism is first order in $\beta$. Therefore, I can't help but think that Purcell's explanation is fundamentally flawed.

Going back to the charge-current transformation, if we use geometric units we have:

$$\rho' = \gamma \left(\rho - \beta J \right) $$

I _think_ that in SI units, the second term looks more like -v/c^2 J, when you choose non-geometric units where c is not unity. That would be units of (columobs / meter^2 second) / (meters/second) = (coulombs/meter^3) which looks right.

And to first order $\gamma=1$, so the only first order term is $\approx$ $-\beta$ J. Or - v/c^2 J in non-geometric units. So, why does Purcell attribute magnetism to "length contraction" at all?

On a practical level, I think this only emphasises the need to use the full Lorentz transform - attributing it to "length contraction" seems to me to be misguided.

On a side note, I have the impression that the OP isn't familiar with the Lorentz transformation (I could be wrong on that), but if that's the issue, I think the OP needs to be at least curious enough to open another thread on that topic. Though I also suspect that it's something best learned from something other than a PF post.