LR Circuit: Answers to Common Questions

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Homework Help Overview

The discussion revolves around an LR circuit involving a switch, a bulb, and a solenoid. Participants are examining the behavior of current in the circuit when the switch is opened, particularly focusing on the implications for the bulb's brightness and the current through the solenoid.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are questioning the behavior of current immediately after the switch is opened, with some suggesting that the current does not drop to zero instantly but decreases exponentially. Others are exploring the relationship between the current through the solenoid and the bulb, and whether energy is stored in the coil.

Discussion Status

The discussion is ongoing, with various interpretations being explored regarding the initial conditions when the switch is opened. Some participants have provided hints and questions aimed at clarifying the situation, while others express confusion over the wording of the problem and its implications.

Contextual Notes

There is uncertainty regarding the resistance of the solenoid and the initial current values, which may affect the understanding of the circuit's behavior. Participants are also reflecting on the nature of energy conservation in the context of the problem.

Anirudhhades
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Homework Statement
Guys in this question I think that once the switch is opened the current doesn’t immediately drop to zero but reduces at some exponential rate but at the very instant the source of EMF is removed the currrent in the circuit must still be equal to the current when switch was closed and hence the brightness of the bulb remains same

The options are:
A) Remains same as before
b) The bulb goes out
C)Glows very brightly

According to answer key the answer is C)
But I think the answer should be A)


Please help me out!
Relevant Equations
I=I (e^-Rt/L)
image.jpg
 
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Anirudhhades said:
Homework Statement:: Guys in this question I think that once the switch is opened the current doesn’t immediately drop to zero but reduces at some exponential rate but at the very instant the source of EMF is removed the currrent in the circuit must still be equal to the current when switch was closed and hence the brightness of the bulb remains same

The options are:
A) Remains same as before
b) The bulb goes out
C)Glows very brightly

According to answer key the answer is C)
But I think the answer should be A)Please help me out!
Relevant Equations:: I=I (e^-Rt/L)

View attachment 269810
The branch with the bulb and the switch are conected parallel with the coil. What do you think where is the current higher when the switch is closed? through the bulb or through the coil?
 
Aargh! Another poorly written homework problem. Is there any prior information about what the resistance of the solenoid is (or the current through it when the switch is opened)? Maybe from another question or lecture. The question relates to how much solenoid current compared to the lamp current.

Theoretically, inductors (solenoids) have zero resistance. In the real world they don't, and this circuit makes no sense unless that current is limited somehow.
 
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A badly written question, but can you answer these hints?:
1) While switched on, does the the coil have a current through it?
2) While switched on, does the the coil have energy stored? If so, what sort?
3) While the switch is (virtually instantly) being opened, what can you say about the time the current (from the battery) takes to drop to zero?
4) While the switch is (virtually instantly) being opened, what can you say about the rate of change of current through the coil? And what can you then say about the induced emf across the coil?
 
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Even the answers are written poorly.

I think the correct answer is B) The bulb goes out EVENTUALLY. It's the only thing I'm sure of since the only energy source is removed and I don't believe in perpetual motion machines. But along those lines, your answer of A) It remains the same as before, can be true initially, but it can't stay that way forever.

I'm sorry you have to deal with this, but there is some good learning possible, follow up with the questions from @Steve4Physics
 
@DaveE based Off of the options given I think they are asking initially when the source is cut
 
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Steve4Physics said:
A badly written question, but can you answer these hints?:
1) While switched on, does the the coil have a current through it?
2) While switched on, does the the coil have energy stored? If so, what sort?
3) While the switch is (virtually instantly) being opened, what can you say about the time the current (from the battery) takes to drop to zero?
4) While the switch is (virtually instantly) being opened, what can you say about the rate of change of current through the coil? And what can you then say about the induced emf across the coil?
Thanks a lot
 
Anirudhhades said:
Homework Statement:: Guys in this question I think that once the switch is opened the current doesn’t immediately drop to zero but reduces at some exponential rate but at the very instant the source of EMF is removed the currrent in the circuit must still be equal to the current when switch was closed and hence the brightness of the bulb remains same
It's not clear what you mean when you say "the currrent in the circuit." There are three branches in the circuit, and each has a current running through it. Which current stays the same when the switch is opened?
 
Anirudhhades said:
Thanks a lot
Hi Anirudhhades. If you attempt to answer my 4 hint-questions (post #4) I'll explain why these lead to choice C.
 

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