MacLaurin Approximation for 1-cos(x)/x

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The forum discussion focuses on finding the Maclaurin approximation for the integral of (1 - cos(x))/x from 0 to 1. Participants emphasize the importance of starting with the Maclaurin series for cos(x), which is expressed as cos(x) = 1 - (x^2)/2! + (x^4)/4! + ... The discussion highlights the challenge of evaluating the limit as x approaches 0, where the first term of the series leads to an indeterminate form. The correct approach involves simplifying (1 - cos(x))/x using the series expansion.

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integrate from 0 -> 1
(1-cosx)/x dx

find maclorein approximation
this has been killing me any ideas??
 
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Start with the Maclauren series for cosx, do you know it?
 
rock.freak667 said:
Start with the Maclauren series for cosx, do you know it?

well one of my issues atm that forgot to add on there is the first term is over zero isn't it? due to the lower bounds and the serious should be 1-1/2x^2 +1/24x^4...
if that helps you find where i am lost :)
 
so

cos(x)=1-\frac{x^2}{2!}+\frac{x^4}{4!}+...

what is 1-cos(x)? Then what is (1-cosx)/x ?
 

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