- Problem Statement
- Show that the value of ##\int_0^1\sqrt(1-cosx)dx## is less than or equal to ##\sqrt2##

- Relevant Equations
- ##1\ge \cos x\ge-1##

Show that the value of ##\int_0^1\sqrt(1-cosx)dx## is less than or equal to ##\sqrt2##

##1\ge cos x\ge-1##

The problem is a worked one but I am just confused by a simple thing. We integrate the function f ##\int_0^1\sqrt(1-cosx)dx in the interval [0,1] but I don't understand that what stands for x-axis? Radian, degree or nothing? I know this does not affect the maximum and minumum values of cos function but how should I think in such a situation?

Source: Thomas Calculus.

##1\ge cos x\ge-1##

The problem is a worked one but I am just confused by a simple thing. We integrate the function f ##\int_0^1\sqrt(1-cosx)dx in the interval [0,1] but I don't understand that what stands for x-axis? Radian, degree or nothing? I know this does not affect the maximum and minumum values of cos function but how should I think in such a situation?

Source: Thomas Calculus.

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