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## Homework Statement

A magnetic dipole is oriented in a loop of wire of N turns and radius a so that the dipole vector is parallel to the normal of the loop. The loop is connected to a galvanometer, and the active resistance of the circuit is R.

The dipole is moved away from the loop, and in the process a total charge q passes through the galvanometer. Find [itex]\mu[/itex], the magnetic dipole magnitude, in terms of the given variables.

## Homework Equations

Ohm's law

Faraday's law of induction

## The Attempt at a Solution

From Faraday's law:

[tex]

\varepsilon = -\frac{\partial \Phi_B}{\partial t}

[/tex]

From Ohm's law:

[tex]

\varepsilon = IR = \frac{d q}{dt}R = -\frac{\partial \Phi_B}{\partial t}

[/tex]

Integrating, we get:

[tex]

qR = -\Phi_B

[/tex]

Where, I think, [itex]\Phi_B[/itex] represents the initial magnetic flux.

Now I have two questions:

- Is what I have done so far correct?
- How am I supposed to find the magnetic flux?