Magnetic dipole moment energy question

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SUMMARY

The discussion centers on the calculation of magnetic dipole moment energy in an external magnetic field, specifically using the equations U_m = (1/2)∫A·J dr³ = (1/2)μ·B and F = ∫J×B dr³. The discrepancy arises from the inclusion of a factor of 1/2 in the energy equation, which accounts for double counting in current distributions. The positive sign in the first equation is attributed to a constant current maintained by an EMF source, while the second equation reflects a scenario without energy input, leading to a negative gradient of energy. Both approaches yield the same force despite the differences in energy calculations.

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Hello, I have this problem. I calculated the dipole energy of a dipole moment in an external field using the equation U_m=\frac{1}{2}\int\vec{A}\vec{J}dr^3=\frac{1}{2} \vec{\mu}.\vec{B} however when the force on a dipole is calculated using \int\vec{J}\times\vec{B}dr^3 the formula obteined for the energy is -\vec{\mu}.\vec{B}
I don't understand the difference, are they supposed to be defferent?
 
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The 1/2 in your first equation arises because the integral is over all current distributions. The 1/2 takes care of double counting that takes place in that case.
The B field in the second equation is due to only external currents (not part of mu), so the 1/2 does not arise.

The + sign in the first equation is due to the fact that the current is kept constant by an EMF source that provides energy to keep the current constant. Then, the force is given by +grad U. In the second equation, no energy is supplied, so F= -grad U.
Each case thus gives the same force.

You can look at <http://arxiv.org/pdf/0707.3421.pdf>
 
Thanks, I will take a look
 

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