- #1

- 559

- 8

## Homework Statement

## Homework Equations

## The Attempt at a Solution

[tex]B=\frac{\mu_{0}I}{4\pi}\int \frac{dl\times \hat{r}}{r^{2}}=\frac{\mu_{0}I}{4\pi r^{2}}\int dl\times \hat{r}[/tex]

So I think since when you cross dl with r, you end up with just dl.

[tex]\frac{\mu_{0} I}{4\pi r^{2}}\int dl[/tex]

l=rθ so dl=rdθ, substituting:

[tex]\frac{\mu_{0} I}{4\pi r^{2}}\int rd\theta=\frac{\mu_{0} I}{4\pi r}\int d\theta=\frac{\mu_{0} I}{4\pi r}\theta[/tex]

Plugging in values I end up with: 2.618x10

^{-7}T

Just need someone to look over work/logic, I think it's correct.