Magnetic Field Flux Through a Circular Loop Near an Infinite Wire

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SUMMARY

The discussion focuses on calculating the magnetic field flux through a circular loop of radius 'a' positioned at a distance 'r' from an infinitely long current-carrying wire with current 'I'. The magnetic field (B) is defined as B = (μ₀I)/(2πx), where x is the perpendicular distance from the wire. The user explores the integration of the differential flux B.dA over the loop, acknowledging the complexity of the integral involved. The consensus confirms that the approach is correct, although it does not introduce new physics compared to simpler configurations.

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  • Understanding of magnetic fields and their calculations
  • Familiarity with calculus, specifically integration techniques
  • Knowledge of Ampère's Law and its application to infinite wires
  • Basic concepts of magnetic flux and its physical significance
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  • Study the derivation of magnetic fields around infinite current-carrying wires
  • Learn advanced integration techniques for complex geometries
  • Explore the application of Ampère's Law in different configurations
  • Investigate the concept of magnetic flux in various shapes beyond circular loops
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Mandeep Deka
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1. A circular loop, (of radius 'a') is placed with its center at a distance 'r' from an infinitely long current carrying wire, (carrying current 'I'), in the same plane as that of the wire. For, a<r, find the flux of magnetic field through the loop.



2. Differential Flux=B.dA, whose integral over a surface gives the net flux through the surface. B (at a distance x, for a infinitely straight wire carrying current I)= (mu naught. i)/2.pi.x.



3. Since the magnetic field,(B) due to a infinite st. wire is a function of perpendicular distance (x) from the wire, we consider an elementary rectangular segment of plane , enclosed by the loop at a distance (r+x) from the wire with length l=2[(a^2-x^2)^0.5] and breadth dx (differential increment in perpendicular distance from the wire). So now if we have the elementary flux as (B.l.dx), we can integrate x, in the expression from -a to +a, to obtain the flux. But the integration is a bit complicated, (though the answer be determined) which puts me into a little doubt whether my approach to solve the problem is correct! I would like u to solve the problem and check whether my process is correct or not.
 
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Your method is correct and, yes, it leads to a complicated integral. If it makes you feel any better, this problem (in my opinion) does not teach you any new physics beyond what the simpler case of the rectangular loop parallel to the wire teaches.
 
ya m aware of that.. i jus wanted to know if i was havng the corrrct approach...
by d way thanks.
 

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