Magnetic field for azimuthal current

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The discussion focuses on finding a suitable function f(r, θ) for a current density in a spherical shell that results in an analytically solvable magnetic field. The current density is defined in the azimuthal direction, leading to complex integrals when applying the Biot-Savart law. The author seeks suggestions for functions with sufficient symmetry to simplify calculations, as previous attempts have been unsuccessful. The shell is described as carrying a uniform charge density and spinning with angular speed, generating an azimuthal current. The magnetic fields inside and outside the shell can be derived from the current density using the magnetic vector potential.
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I am working with a current density defined in a spherical shell S(a, b) (inner radius a and outer radius b). The current density is completely in the azimuthal direction:

J = f(r,\theta) \hat{\phi}

I am trying to pick some simple (but non-trivial) f(r,\theta) so that the magnetic field has an analytical solution. All the functions I've tried lead to very complicated integrals in the Biot-Savart law, and I can't seem to find anything with enough symmetry to use an Ampere loop.

Does anyone know of any suggestions?
 
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Consider the shell carrying charge with uniform charge density ##\rho## and a volume element ##dV=r^2dr~\sin\theta d\theta~ d\phi##. If the shell spins with angular speed ##\omega##, the volume element produces an azimuthal current $$dI=\frac{dq}{dt}=\frac{\omega~dq}{2\pi}={\omega~\rho r^2~dr~\sin\theta d\theta};~~~~~(\omega=d\phi/dt)$$
The area element perpendicular to the azimuthal direction is ##dA=r~d\theta~dr## in which case you can write the current density as $$\vec J=\omega \rho r \sin\theta~\hat \phi=\rho~\vec {\omega} \times \vec r.$$
You get the magnetic fields both inside and outside the shell by using the current density to find the magnetic vector potential in the two regions (a) ##r>r'## outside and (b) ##r<r'## inside. $$\vec A(\vec r)=\frac{\mu_0}{4\pi}\int \frac{\vec J(\vec r')}{|\vec r-\vec r'|}~dV'$$Then ##\vec B=\vec {\nabla}\times \vec A##.
 

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