Magnetic Field from a Single Electron

Click For Summary

Discussion Overview

The discussion revolves around the nature of the magnetic field produced by a single electron in motion, particularly addressing the apparent contradiction between the changing magnetic field observed in a lab frame and the lack of radiation from a non-accelerating charge. Participants explore concepts related to electromagnetic fields, radiation, and the implications of different reference frames.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants note that a steady electric field from a string of electrons in a wire results in a static magnetic field that does not propagate electromagnetic waves.
  • One participant argues that while an observer in the lab frame sees a changing magnetic field (dB/dt ≠ 0), this does not lead to radiation because radiation is associated with acceleration, not velocity.
  • Another participant references the Lienard-Weichert potential to explain that radiation terms are proportional to acceleration, suggesting that the non-zero dB/dt does not contribute to radiation.
  • Some participants emphasize that radiation occurs only if the electron is accelerating, reiterating this point multiple times throughout the discussion.
  • One participant introduces the concept of stored energy in the magnetic field of the moving electron, comparing it to the reactive near field of an antenna and discussing the phase relationship between electric and magnetic fields in sinusoidal cases.

Areas of Agreement / Disagreement

Participants generally agree that radiation does not occur for a non-accelerating electron, but there is ongoing debate about the implications of the changing magnetic field in different reference frames and the nature of the stored energy in the magnetic field.

Contextual Notes

The discussion includes references to Noether's theorem and Maxwell's equations, but does not resolve the mathematical details or assumptions underlying the claims made by participants.

Who May Find This Useful

This discussion may be of interest to those studying electromagnetism, special relativity, or the behavior of charged particles in motion, particularly in relation to radiation and field transformations.

kq6up
Messages
366
Reaction score
13
I understand that an electric field from a string of electrons traveling in a wire gives a steady (magneto-static) field. Since this field is static, it will not cause a EM wave to propagate away from it. I also understand that individual charges that are not accelerating are not radiating since steady motion is frame dependent, and all interesting physics should be frame independent (Noether's Thm).

However, it seems if you were an observer measuring a magnetic field of an electron traveling past you. That magnetic field would be changing in the lab frame. Therefore, the dB/dt term would not be zero. This seems like it should cause a propagating EM wave by my thought experiment. Could someone help me with this apparent contradiction.

Thanks,
Chris
 
  • Like
Likes   Reactions: Dreed42
Physics news on Phys.org
The magnetic and electric field are tightly related with each other. In particular, if you have an electron traveling with constant velocity and you see a magnetic field then if you go to the electron rest frame, the Lorentz transformation will mix the magnetic and electric field and the final result is that you'll just see an electric field.
 
Indeed, in the rest frame of the electron there is only E field in a steady state. What explains the lack of radiation in the lab frame?

Chris
 
You only have radiation if the electron is accelerating.
 
  • Like
Likes   Reactions: Symmetry777
kq6up said:
That magnetic field would be changing in the lab frame. Therefore, the dB/dt term would not be zero. This seems like it should cause a propagating EM wave by my thought experiment.
If you look at the Lienard Weichert potential you see that the radiation terms are proportional to acceleration, not velocity. So although there is a non-zero dB/dt, the energy and fields from that term do not radiate.

http://en.wikipedia.org/wiki/Liénard–Wiechert_potential
 
  • Like
Likes   Reactions: kq6up
Einj said:
You only have radiation if the electron is accelerating.

Yes, that is what I clarified in my first post. I know that it doesn't. I just need the mathematical explanation as to why not as I try to visualize what is going on with Maxwell's Equations in such a case. I will check out the Wiechert potentials.

Regards,
Chris
 
kq6up said:
I understand that an electric field from a string of electrons traveling in a wire gives a steady (magneto-static) field. Since this field is static, it will not cause a EM wave to propagate away from it. I also understand that individual charges that are not accelerating are not radiating since steady motion is frame dependent, and all interesting physics should be frame independent (Noether's Thm).

However, it seems if you were an observer measuring a magnetic field of an electron traveling past you. That magnetic field would be changing in the lab frame. Therefore, the dB/dt term would not be zero. This seems like it should cause a propagating EM wave by my thought experiment. Could someone help me with this apparent contradiction.

Thanks,
Chris
kq6up said:
I understand that an electric field from a string of electrons traveling in a wire gives a steady (magneto-static) field. Since this field is static, it will not cause a EM wave to propagate away from it. I also understand that individual charges that are not accelerating are not radiating since steady motion is frame dependent, and all interesting physics should be frame independent (Noether's Thm).

However, it seems if you were an observer measuring a magnetic field of an electron traveling past you. That magnetic field would be changing in the lab frame. Therefore, the dB/dt term would not be zero. This seems like it should cause a propagating EM wave by my thought experiment. Could someone help me with this apparent contradiction.

Thanks,
Chris
 
The magnetic field of the moving electron contains stored energy. It is therefore reactive and does not represent power radiated. It is equivalent to the magnetic reactive near field of an antenna. If an electric field is being used to accelerate the electron, then that has a reactive electric component corresponding to the electric reactive near field of an antenna. In a sinusoidal case, the accelerating electric field and the magnetic field of the electron are 45 degrees out of phase; half the energy is stored and half radiated.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 20 ·
Replies
20
Views
5K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 24 ·
Replies
24
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K