Magnetic field in a closed path

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Homework Help Overview

The discussion revolves around calculating the magnetic field at a specific point due to a closed path of current-carrying segments. The problem involves applying the Biot-Savart law and analyzing contributions from various segments of the path.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the contributions of different segments to the magnetic field, questioning the effects of segments 5-6 and 6-1. There is an exploration of the direction of the magnetic field and the total contributions from all segments.

Discussion Status

Some participants have provided calculations and expressed uncertainty about the direction of the magnetic field from specific segments. There is an ongoing exploration of the total magnetic field and its direction, with some participants suggesting alternative approaches to simplify the calculations.

Contextual Notes

Participants reference specific values and results from a textbook, indicating a potential discrepancy between their calculations and the expected results. There is mention of homework constraints and the need to adhere to specific problem setups.

Faefnir
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Homework Statement


Find (a) the module and (b) the direction, entering or exiting the page plane, of the magnetic field at point P, knowing that a = 4.7 cm and i = 13 A

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Homework Equations


Biot-Savart law

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The Attempt at a Solution



For 1-2 and 4-5 segments, B = 0 because sin θ = 0 for all segment points.

Taking the 2-3 segment

R = distance from P to the wire (2-P line)
r = distance from P to the point 3. Assume the point 3 as the infinitesimal segment ds (3-P line)
s = wire length (2-3 line)

From the first rectangle triangles law

R = r sin (π-θ) = r sin (θ) ⇒ sin (θ) = R/r

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r is triangle's hypotenuse with s and R as catetis

r2 = R2 + s2

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Solving the integral

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after a few steps

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Regardless of the numerical result, the final formula I got is right, or have I made any mistakes?

Thanks in advance
 

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What about the magnetic field from segments 5-6 and 6-1?
 
kuruman said:
What about the magnetic field from segments 5-6 and 6-1?

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Is this both of them or just one? What about the total? What about the direction?
 
Both of 5-6 and 6-1.

About total and direction:
2-3 is entering
6-1 is exiting
Not sure about horizontal segments (3-4 and 5-6): Can you help me? (yes, I know sounds like ready-made food)

I supposed to rotate the image by 90° clockwise:
3-4 is entering
5-6 is exiting

So, the total is -1.86 · 10-5
The book reports 20 μA for a entering current (from chapter 29 exercises, Halliday-Resnick-Walker, Electromagnetism and Optics, 7th edition)
 
Last edited:
Faefnir said:
-1.86 · 10-5
Can you show me how you got this number? Please use the final equation with symbols that you used.
Faefnir said:
The book reports 20 μA for a entering current (from chapter 29 exercises, Halliday-Resnick-Walker, Electromagnetism and Optics, 7th edition)
Do you actually mean μA? If so, what current is this?
 
Solved. Taking ds verse agrees as the one of the current

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so
|B| ≅ |-2 · 10-5| T ≅ 2 · 10-5 T
The minus sign suggests an entering direction for the magnetic field
 

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I agree with your answer. Now that you have solved your problem, I will show you an easier way than calculating the separate contributions from each segment. Suppose you found an expression for the B-field at the corner of a regular square. The field for the loop in the problem is the superposition of two squares one of side ##2a## and counterclockwise current and one with side ##a## and clockwise current (see figure below). So once you find the expression for the square, you reuse it for the smaller square with a negative sign because the current is reversed.
SquareLoop.png
 

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