# Magnetic Field Strength and Webers

1. Jul 25, 2011

### ja_tech

OK well, this isn't a question as such, more a conceptual thing...

The formula, B=(Weber)/(Area) gives the magnetic field strength, B in Tesla... .

But when I rearrange in terms of magnetic flux, it's obviously (Tesla) X (Area).

My question is, how is the flux (lines of force) defined by the product of the field strength (B) and the area???

One weber is equal to T m^2 but how can I think of this in terms of lines of force?

Im sorry that I may have come across quite confusingly.

thanks

2. Jul 25, 2011

### tiny-tim

hi ja_tech!

lines of force aren't real …

(just as lines of latitude and longitude on the Earth aren't real)

of course we must draw them parallel to the field direction, but we can draw as many as we like

we choose to draw them in proportion to the strength of the field

also, if we double the (small) area, obviously we must also double the number of lines through it, so they must be in proportion to area also

so lines of flux are proportional to area times field strength: Wb ~ T m2

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