Magnetic field vs Electric field

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SUMMARY

This discussion centers on the simulation of ferrous particles moving around a cylindrical permanent magnet using an electric field in software that only allows for electric field settings. Participants clarify that while magnetic and electric fields are orthogonal, substituting a magnetic field with an equivalent electric field to achieve the same attraction force is generally not feasible due to the dependency of magnetic force on particle velocity. The equation B = vχE/sqrt(c) is referenced, highlighting the relationship between velocity, electric field, and magnetic induction.

PREREQUISITES
  • Understanding of magnetic and electric field interactions
  • Familiarity with the behavior of ferrous particles in magnetic fields
  • Knowledge of electromagnetic theory, specifically the Lorentz force
  • Proficiency in using simulation software for electromagnetic modeling
NEXT STEPS
  • Research the Lorentz force and its implications for charged and neutral particles
  • Explore simulation software capabilities for modeling magnetic and electric fields
  • Study the derivation and applications of the equation B = vχE/sqrt(c)
  • Investigate methods for simulating particle behavior in varying electromagnetic fields
USEFUL FOR

Physicists, electrical engineers, and simulation software developers interested in electromagnetic field interactions and particle dynamics.

Methavix
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Hi all,
I have to simulate the behavior of a stream of ferrous particles (no electrical charge) that moves axially around a cylindrical permanent magnet. The software I use allows me to set only an electric field. Can i set an electric field equivalent to the magnetic field? I know the magnetic induction, and I know material, size and velocity of particles.
thanks
 
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You know the magnetic and electric fields are orthogonal, right??

And both are transverse (orthogonal) to the direction of propagation.
 
yes, but this is not regarding my problem
i would substitute the magnetic field and ferrous particles with an equivalent electric field and charged particles, in order to have the same final effect (i.e. the same attraction force).
 
I don't think that is possible in general since the magnetic force depends on the velocity. Unless the software would allow you to make the e-field depend on the velocity.
 
Naty1 said:
You know the magnetic and electric fields are orthogonal, right?

That's not true. I can have an E field parallel to a B field.
 
Hi there all,
I want to know something about this equation specially about how we can derive it from the simple ones
B=vχE/sqr(c)​
where, v is velocity of the source of E and c is speed of light.

tnx in advance,
 
The motion will be the same as that for small particles with induced electric dipole moments in an electric field which is the same as the actual B field.
 

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