Magnetic Field with Time Dependence

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Homework Help Overview

The problem involves calculating the induced electromotive force (EMF) in a circular coil due to a time-dependent magnetic field. The coil has a specific number of turns and dimensions, and the magnetic field varies over time, as indicated by an attached graph.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss calculating the area of the coil and the slope of the magnetic field over time. There are attempts to find the rate of change of magnetic flux and questions about the arithmetic involved in these calculations. Some participants express uncertainty about whether their reasoning is flawed or if they are missing steps.

Discussion Status

Participants have provided hints and guidance on checking arithmetic and clarifying the relationship between the rate of change of magnetic flux and induced EMF. There is an ongoing exploration of the calculations, with some participants revisiting their work to ensure accuracy.

Contextual Notes

There is a focus on the correct conversion between volts and millivolts, and participants are working within the constraints of the problem as presented, including the specific time points and values from the graph.

deenuh20
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Homework Statement



A magnetic field with the time dependence shown in the figure below is at right angles to a N=197 turn circular coil with a diameter of d=4.2 cm.


What is the induced EMF in the coil at t=7.5ms in mV?

See attached graph


Homework Equations



|EMF|= N*|change in magnetic flux/change in time|



The Attempt at a Solution



First Attempt:
I first found Area by pi*(.042m/2)^2 and got 0.001385m^2. Then, I found the slope of the line between 5 and 10 ms, which was -0.006 T/ms. Then, I multiplied this slope by 7.5ms to see what the magnetic field at 7.5ms was, and I got -0.45T. Then, I used this value to find the magnetic flux which was (0.001385m^2)(-0.045T) and got -6.235*10^-5. Then, I took this value, divided by 7.5ms, and got -0.00831. Then, I multiplied this by 197 and got -1.63707 V. I divided this by 1000 and got -0.001637mV, but this answer is not being accepted.
 

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deenuh20 said:
First Attempt:
I first found Area by pi*(.042m/2)^2 and got 0.001385m^2.
Good.
Then, I found the slope of the line between 5 and 10 ms, which was -0.006 T/ms.
All good, so far. And this is almost all you need.

Hint: You've already calculated the rate of change of the field, so what's the rate of change of the flux?

(The flux doesn't matter--only the rate of change of the flux.)
 
To find the rate of change of the flux, I did:

(B @ 10ms * Area) - (B @ 5ms * Area) all divided by (10ms-5ms)
(-0.01T*0.001385)-(0.02T*0.001385)/(5ms) and got 4.155*10^-5 as the rate of change of the flux

I then multiplied 4.155*10^-5 by 197, and got 0.008185, which I then divided by 1000, and got 8.18535mV, however, this is still not the right answer.

Is my reasoning flawed or am I missing an essential step?
 
deenuh20 said:
To find the rate of change of the flux, I did:

(B @ 10ms * Area) - (B @ 5ms * Area) all divided by (10ms-5ms)
(-0.01T*0.001385)-(0.02T*0.001385)/(5ms) and got 4.155*10^-5 as the rate of change of the flux
Your reasoning is fine; check your arithmetic.
 
Ok, let's try this step by step:

deenuh20 said:
To find the rate of change of the flux, I did:

(B @ 10ms * Area) - (B @ 5ms * Area) all divided by (10ms-5ms)
(-0.01T*0.001385)-(0.02T*0.001385)/(5ms) and got 4.155*10^-5 as the rate of change of the flux

I redid my arithmetic here, and as the rate of change of flux, I now got -0.00831

Is this correct?

Also, Thank you very much for your help!:smile:
 
Looks good to me. (Units: T/s)
 
deenuh20 said:
I redid my arithmetic here, and as the rate of change of flux, I now got -0.00831

Ok, now that I have the rate of change of flux, in order to find the induced EMF, in mV:

I multiplied the rate of change of flux by the number of turns (197)

(-0.00831 T/s)(197)= -1.63707 V

then to get mV: -1.63707 V/1000 = -0.001637 mV

Correct?


If this is the correct way to do it, it is still the wrong answer when I enter it in my homework online :confused:
 
deenuh20 said:
I multiplied the rate of change of flux by the number of turns (197)

(-0.00831 T/s)(197)= -1.63707 V

then to get mV: -1.63707 V/1000 = -0.001637 mV


I got it! I figured out what I was doing wrong. I had to divide by 10^-3, not 1000, and got 1637.07 mV, which was the right answer. Thanks for all your help!
 
deenuh20 said:
then to get mV: -1.63707 V/1000 = -0.001637 mV
Check this step. (How many mV in a Volt? :wink: )

(edit: Looks like you figured that out on your own!)
 
Last edited:

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